In: Statistics and Probability
You roll a die, winning nothing if the number of spots is even, $3 for a 1 or a 3, and $18 for a 5.
a) Find the expected value and standard deviation of your prospective winnings.
b) You play three times. Find the mean and standard deviation of your total winnings.
c) You play 30 times. What is the probability that you win at least $160?
Probability of even number= 3/6= 0.5
Probability of 1 or 3= 2/6= 0.3333
Probability of 5= 1/6= 0.1667
X | P(X) | X*P(X) | X2 * P(X) |
0 | 0.5 | 0 | 0 |
3 | 0.3333 | 0.9999 | 2.997 |
18 | 0.1667 | 3.0006 | 54.0108 |
Total | 1 | 4.0005 | 57.0078 |
a) From the above table,
Expected value,
b) Let Y=X1+X2+X3
Where Xi is winning amount for the ith game; i=1,2,3
the expected value is given by,
c) Let X be the amount won in the game.
For 30 trials,
Mean= 30*4.0005= 120.0015
From standard normal table, P(z>1.14)=0.1271
Required Probability= 0.1271.
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