Question

wite a program in C to print a right and left pointing arrow pattern using '#' symbol. Do so within 10 lines i.e upper half of the occupies 5 lines and lower half occupies other 5 lones.

User will enter 'R' or'r' for printing right pointing arrow. 'l' or 'L' for left pointing arrow.'k'' for invalid option.

You must use if-else and while loop for do this.

Answer 1

Please find the code below::

#include<stdio.h>
#include<string.h>
int main(){

   char choice;
   while(1){
       printf("Enter your choice (L l R r k K) : ");
       scanf("%c",&choice);
       while(choice=='\n')
       scanf("%c",&choice);
       if(choice=='l' ||choice=='L'){
           printf(" #\n");
           printf(" #\n");
           printf(" #\n");
           printf(" #\n");
           printf("#############################\n");
           printf("#############################\n");
           printf(" #\n");
           printf(" #\n");
           printf(" #\n");
           printf(" #\n");
       }else if(choice=='R'||choice=='r'){
           printf(" #\n");
           printf(" #\n");
           printf(" #\n");
           printf(" #\n");
           printf("#############################\n");
           printf("#############################\n");
           printf(" #\n");
           printf(" #\n");
           printf(" #\n");
           printf(" #\n");
       }else if(choice =='k' || choice =='K'){
           break;
       }else{
           printf("Please enter valid choice....\n");
       }
   }
   return 0;
}

output: