Question

USING a LOOP for C++ In this lab the completed program should print the numbers 0 through 10, along with their values multiplied by 2 and by 10. You should accomplish this using a for loop instead of a counter-controlled while loop. Instructions Write a for loop that uses the loop control variable to take on the values 0 through 10. In the body of the loop, multiply the value of the loop control variable by 2 and by 10. Execute the program by clicking the Run button at the bottom of the screen. Is the output the same? prewritten code is: // NewMultiply.cpp - This program prints the numbers 0 through 10 along // with these values multiplied by 2 and by 10. // Input: None // Output: Prints the numbers 0 through 10 along with their values multiplied by 2 and by 10. #include #include using namespace std; int main() { string head1 = "Number: "; string head2 = "Multiplied by 2: "; string head3 = "Multiplied by 10: "; int numberCounter; // Numbers 0 through 10 int byTen; // Stores the number multiplied by 10 int byTwo; // Stores the number multiplied by 2 const int NUM_LOOPS = 10; // Constant used to control loop // This is the work done in the housekeeping() function cout << "0 through 10 multiplied by 2 and by 10." << endl; // This is the work done in the detailLoop() function // Write your for loop here. // This is the work done in the endOfJob() function return 0; } // End of main()

Answer 1

#include <iostream>

using namespace std;

int main()
{
string head1 = "Number: ";
string head2 = "Multiplied by 2: ";
string head3 = "Multiplied by 10: ";
int numberCounter;
int byTwo;
int byTen;
const int NUM_LOOPS = 10;
cout << "0 through 10 multiplied by 2 and by 10." << endl;
//write a for loop
for(numberCounter=0;numberCounter<=NUM_LOOPS;numberCounter++)
{
byTwo=2*numberCounter;
byTen=10*numberCounter;
//print the values according to a specific format
cout<<head1<<numberCounter<<" "<<head2<<byTwo<<" "<<head3<<byTen<<endl;
}

return 0;
}

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