In: Economics
machine X
Initial cost = $100.000
Benefit/year = 20,000 for first 10 years and 10,000 for the next 5 years
life= 15 years
salvage value= 35000
MARR 8%
Zambrota Inc, an Italian company, is considering to facilitate Machine X for their plant in Omaha. The benefit & cost information for Machine X project is shown in Chart 4. The net benefit ( Benefit – Cost ) by using PW method is
To do this we have to calculate the present value of all the benefits, salvage value, and cost.
Present value is the value in the present, of a sum of money, in contrast to some future value it will have when it has been invested at compound interest.
Present value = future value/(1+interest rate)^time
The present value of the benefit in year 1
= 20,000/(1+8%)^1
=$18,518.52
The present value of the benefit in year 2
= 20,000/(1+8%)^2
= $17,146.78
The present value of the benefit in year 3
= 20,000/(1+8%)^3
= $15,876.64
The present value of the benefit in year 4
= 20,000/(1+8%)^4
= $14,700.60
and so on..
This cash flow will change from11th year and the cash flow will be $10000 per year.
The present value of the benefit in year 11
= 10,000/(1+8%)^11
= $4,288.83
The present value of salvage value
= 35,000/(1+8%)^15
= $11,033.46
In table form it looks like this
Year | Cash flow | PV |
0 | -$100,000 | -100,000.00 |
1 | $20,000 | $18,518.52 |
2 | $20,000 | $17,146.78 |
3 | $20,000 | $15,876.64 |
4 | $20,000 | $14,700.60 |
5 | $20,000 | $13,611.66 |
6 | $20,000 | $12,603.39 |
7 | $20,000 | $11,669.81 |
8 | $20,000 | $10,805.38 |
9 | $20,000 | $10,004.98 |
10 | $20,000 | $9,263.87 |
11 | $10,000 | $4,288.83 |
12 | $10,000 | $3,971.14 |
13 | $10,000 | $3,676.98 |
14 | $10,000 | $3,404.61 |
15 | $10,000 | $3,152.42 |
Salvage value in year 15 | $35,000.00 | $11,033.46 |
Total | $163,729.06 |
The present value of benefits are $163,729.06. the present value of cost is 100,000
Net benefits = $163,729.06 - $100,000
= $63,729.06