In: Statistics and Probability
Ho: u= 6 Number of bases personnel have been to
H1: u =/= (not equal) 6 Frequency: 15,16,12,5,1,1 Bases: 0-5,6-10,11-15,16-20,21-25,26-30
? Test the sample results (your collected 50 data points) against the population.
? Explain the relationship between the sample data and the population based on the results of your hypothesis test
Result:
Ho: u= 6 Number of bases personnel have been to
H1: u =/= (not equal) 6
Frequency: 15,16,12,5,1,1 Bases: 0-5,6-10,11-15,16-20,21-25,26-30
? Test the sample results (your collected 50 data points) against the population.
? Explain the relationship between the sample data and the population based on the results of your hypothesis test
| 
 base  | 
 f  | 
 mid x  | 
 f*x  | 
 f*x*x  | 
| 
 0-5  | 
 15  | 
 3  | 
 45  | 
 135  | 
| 
 6-10  | 
 16  | 
 8  | 
 128  | 
 1024  | 
| 
 11-15  | 
 12  | 
 13  | 
 156  | 
 2028  | 
| 
 16-20  | 
 5  | 
 18  | 
 90  | 
 1620  | 
| 
 21-25  | 
 1  | 
 23  | 
 23  | 
 529  | 
| 
 26-30  | 
 1  | 
 28  | 
 28  | 
 784  | 
| 
 Total  | 
 50  | 
 470  | 
 6120  | 





=4.0973
Table value of t with 49 DF at 0.05 level =2.0096
Calculated t =4.0793 > 2.0096 the table value
The null hypothesis is rejected.
We conclude that population mean is different from 6.
This sample is not from the population with mean 6.
| 
 t Test for Hypothesis of the Mean  | 
|
| 
 Data  | 
|
| 
 Null Hypothesis m=  | 
 6  | 
| 
 Level of Significance  | 
 0.05  | 
| 
 Sample Size  | 
 50  | 
| 
 Sample Mean  | 
 9.4  | 
| 
 Sample Standard Deviation  | 
 5.8936  | 
| 
 Intermediate Calculations  | 
|
| 
 Standard Error of the Mean  | 
 0.8335  | 
| 
 Degrees of Freedom  | 
 49  | 
| 
 t Test Statistic  | 
 4.0793  | 
| 
 Two-Tail Test  | 
|
| 
 Lower Critical Value  | 
 -2.0096  | 
| 
 Upper Critical Value  | 
 2.0096  | 
| 
 p-Value  | 
 0.0002  | 
| 
 Reject the null hypothesis  | 
|