In: Statistics and Probability
Ho: u= 6 Number of bases personnel have been to
H1: u =/= (not equal) 6 Frequency: 15,16,12,5,1,1 Bases: 0-5,6-10,11-15,16-20,21-25,26-30
? Test the sample results (your collected 50 data points) against the population.
? Explain the relationship between the sample data and the population based on the results of your hypothesis test
Result:
Ho: u= 6 Number of bases personnel have been to
H1: u =/= (not equal) 6
Frequency: 15,16,12,5,1,1 Bases: 0-5,6-10,11-15,16-20,21-25,26-30
? Test the sample results (your collected 50 data points) against the population.
? Explain the relationship between the sample data and the population based on the results of your hypothesis test
base |
f |
mid x |
f*x |
f*x*x |
0-5 |
15 |
3 |
45 |
135 |
6-10 |
16 |
8 |
128 |
1024 |
11-15 |
12 |
13 |
156 |
2028 |
16-20 |
5 |
18 |
90 |
1620 |
21-25 |
1 |
23 |
23 |
529 |
26-30 |
1 |
28 |
28 |
784 |
Total |
50 |
470 |
6120 |
=4.0973
Table value of t with 49 DF at 0.05 level =2.0096
Calculated t =4.0793 > 2.0096 the table value
The null hypothesis is rejected.
We conclude that population mean is different from 6.
This sample is not from the population with mean 6.
t Test for Hypothesis of the Mean |
|
Data |
|
Null Hypothesis m= |
6 |
Level of Significance |
0.05 |
Sample Size |
50 |
Sample Mean |
9.4 |
Sample Standard Deviation |
5.8936 |
Intermediate Calculations |
|
Standard Error of the Mean |
0.8335 |
Degrees of Freedom |
49 |
t Test Statistic |
4.0793 |
Two-Tail Test |
|
Lower Critical Value |
-2.0096 |
Upper Critical Value |
2.0096 |
p-Value |
0.0002 |
Reject the null hypothesis |