Question

I need to translate my java code into C code.

import java.util.Scanner;
class CS_Lab3 {

public static void main( String args[] ) {

Scanner input = new Scanner( System.in );
// create array to hold user input
int nums[] = new int[10];
int i = 0, truthCount = 0;
char result = 'F', result2 = 'F';

// ask user to enter integers
System.out.print("Please Enter 10 Different integers: ");

// gather input into array
for ( i = 0; i < nums.length; i++ )

nums[i] = input.nextInt();
  
/**********************************
Now I have the input. Remember that for all x P(x)
is equivalent to P(x1) ^ P(x2) ^ ... ^ P(xn)
and there exists an x P(x) is equivalent to P(x1) v P(x2) v ...
v P(xn).
***********************************/

// Here you check the variables against the given statement
// statement 1: For all x ((x < 0) --> x is even)
for ( i = 0; i < nums.length; i++ ) {

// pass values into lessThanZero method
if ( (lessThanZero( nums[i] )) == 'T' )
truthCount += 1;
  
} // end for

/*******************
you want to have truth count == 10 to show that all
values are true.
********************/
if ( truthCount == 10 )
System.out.println( "a) is True" );
  
else
System.out.println( "a) is False" );
  
truthCount = 0;
  
// start of checking nums against statement b
for ( i = 0; i < nums.length; i++ ) {

if ( (lessThanZero(nums[i])) == 'T' )
truthCount += 1;

} // end for

/**********************
You want truthCount > 0 to have a valid statement
***********************/
if ( truthCount > 0 )
System.out.println( "b) is True" );
  
else
System.out.println( "b) is False" );
  
truthCount = 0;

// start of checking nums against statement c
for ( i = 0; i < nums.length; i++ ) {

/*********
Here you want to check if the num[i] < 0 and num[i] / 2 == 0
so you want a method that will check to see if a number is even
**********/
if ( and( lessThanZero(nums[i]), isEven(nums[i]) ) == 'T' )
truthCount += 1;
  
} // end for

if ( truthCount > 0 )
System.out.println( "c) is True" );
  
else
System.out.println( "c) is False" );
  
truthCount = 0;

// start of checking nums against statement d
for ( i = 0; i < nums.length; i++ ) {

if ( or( divByThree(nums[i] - 1), divByTwo(nums[i] - 1) ) == 'T' )
truthCount += 1;

} // end for

if ( truthCount == 10 )
System.out.println( "d) is True" );
  
else
System.out.println( "d) is False" );

} // end main

public static char lessThanZero( int in_int ) {

char output;

if ( in_int < 0 )
output = 'T';
  
else
output = 'F';
  
return output;

} // end lessThanZero

public static char isEven( int in_int ) {

char output;

if ( in_int / 2 == 0 )
output = 'T';
  
else
output = 'F';
  
return output;

} // end isEven

public static char divByThree( int in_int ) {

char output;

if ( in_int % 3 == 0 )
output = 'T';
  
else
output = 'F';
  
return output;

} // end divByThree

public static char divByTwo( int in_int ) {

char output;

if ( in_int % 2 == 0 )
output = 'T';
  
else
output = 'F';
  
return output;

} // end divByTwo

public static char and ( char a, char b ) {

char andResult;

if ( a == 'T' && b == 'T' )

andResult = 'T';
  
else

andResult = 'F';
  
return andResult;

} // end and

public static char or ( char a, char b ) {

char orResult;
  
if ( a == 'F' && b == 'F' )

orResult = 'F';
  
else
  
orResult = 'T';
  
return orResult;
  
} // end or

} // end class

Answer 1

/* C code */

#include <stdio.h>

char lessThanZero( int in_int ) {
  
   char output;
  
   if ( in_int < 0 )
       output = 'T';
  
   else
       output = 'F';
  
   return output;

} // end lessThanZero

char isEven( int in_int ) {
  
   char output;
  
   if ( in_int / 2 == 0 )
       output = 'T';
  
   else
       output = 'F';
  
   return output;

} // end isEven

char divByThree( int in_int ) {
  
   char output;
  
   if ( in_int % 3 == 0 )
       output = 'T';
  
   else
       output = 'F';
  
   return output;

} // end divByThree

char divByTwo( int in_int ) {

   char output;
  
   if ( in_int % 2 == 0 )
       output = 'T';
  
   else
       output = 'F';
  
   return output;

} // end divByTwo

char and( char a, char b ) {
  
   char andResult;
  
   if ( a == 'T' && b == 'T' )
  
       andResult = 'T';
  
   else
  
       andResult = 'F';
  
   return andResult;

} // end and

char or ( char a, char b ) {
  
   char orResult;
  
   if ( a == 'F' && b == 'F' )
  
       orResult = 'F';
  
   else
  
       orResult = 'T';
  
   return orResult;
  
} // end or

int main()
{

   // create array to hold user input
   int nums[10];
   int i = 0, truthCount = 0;
   char result = 'F', result2 = 'F';
  
   // ask user to enter integers
   printf("Please Enter 10 Different integers: ");
  
   // gather input into array
   for ( i = 0; i < 10; i++ )
  
      scanf("%d",&nums[i]) ;
  
   /**********************************
   Now I have the input. Remember that for all x P(x)
   is equivalent to P(x1) ^ P(x2) ^ ... ^ P(xn)
   and there exists an x P(x) is equivalent to P(x1) v P(x2) v ...
   v P(xn).
   ***********************************/
  
   // Here you check the variables against the given statement
   // statement 1: For all x ((x < 0) --> x is even)
   for ( i = 0; i < 10; i++ ) {
  
       // pass values into lessThanZero method
       if ( (lessThanZero( nums[i] )) == 'T' )
           truthCount += 1;
  
   } // end for
  
   /*******************
   you want to have truth count == 10 to show that all
   values are true.
   ********************/
   if ( truthCount == 10 )
       printf( "a) is True " );
   else
       printf( "a) is False " );
  
   truthCount = 0;
  
   // start of checking nums against statement b
   for ( i = 0; i < 10; i++ ) {
  
       if ( (lessThanZero(nums[i])) == 'T' )
           truthCount += 1;
  
   } // end for
  
   /**********************
   You want truthCount > 0 to have a valid statement
   ***********************/
   if ( truthCount > 0 )
       printf( "b) is True " );
   else
       printf( "b) is False " );
  
   truthCount = 0;
  
   // start of checking nums against statement c
   for ( i = 0; i < 10; i++ ) {
  
       /*********
       Here you want to check if the num[i] < 0 and num[i] / 2 == 0
       so you want a method that will check to see if a number is even
       **********/
       if ( and( lessThanZero(nums[i]), isEven(nums[i]) ) == 'T' )
           truthCount += 1;
  
   } // end for
  
   if ( truthCount > 0 )
       printf( "c) is True " );
   else
       printf( "c) is False " );
  
   truthCount = 0;
  
   // start of checking nums against statement d
   for ( i = 0; i < 10; i++ ) {
  
       if ( or( divByThree(nums[i] - 1), divByTwo(nums[i] - 1) ) == 'T' )
           truthCount += 1;
  
   } // end for
  
   if ( truthCount == 10 )
       printf( "d) is True " );
  
   else
       printf( "d) is False " );

} // end main

/* PLEASE UPVOTE */

/* OUTPUT */