An aqueous solution known as Ringer's lactate is administered intravenously to trauma victims suffering from blood...

An aqueous solution known as Ringer's lactate is administered intravenously to trauma victims suffering from blood loss or severe burns. The solution contains the chloride salts of sodium, potassium, and calcium and is also 3.6 mM in sodium lactate (NaC3H5O3). How many grams of sodium lactate are needed to prepare 8.5 liters of Ringer's lactate?

Expert Solution

M= 3.6 mM= 3.6*10^-3 M

V = 8.5 L

number of moles of sodium lactate (NaC3H5O3) = M*V

= (3.6*10^-3)*8.5

=0.0306 mol

Molar mass of sodium lactate (NaC3H5O3) = 112 g/mol

mass of sodium lactate (NaC3H5O3) = Molar mass * number of moles

= 112 * 0.0306

=3.43 g

Answer: 3.43 g

queen_honey_blossom answered 4 weeks ago

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