In: Computer Science
Subject: Computer networks and chapter :packets
1.0. Suppose a link has a propagation delay of 20 µsec and a bandwidth of 2 bytes/µsec.
(a). How long would it take to transmit a 600-byte packet over such a link?
(b). How long would it take to transmit the 600-byte packet over two such links, with a store-and-forward switch in between?
if there is a diagram please draw the diagram
Given that link propagation delay = 20 , and bandwidth of 2 bytes / .
a)
total time = propagation delay + transmission delay.
transmission delay of 600 byte packet using bandwidth of 2 bytes / .
Therefore transmission delay = 600 byte / (2 bytes / ) = 300 .
Total time = 300 + 20 = 320 .
b)
The diagram of the part B is,
Now we have two links of same measurements.
So first of all we have to transfer the packet from sender to the switch then transfer it to the receiver.
We have two links therefore we have two propagation delays, and the packet has to be transmitted by two devices (one sender and switch) therefore two transmission delays.
Therefore total time = 2 times of part (a) total time.
Total time = 2 * 320 = 640 .