Question

For Questions 1-4 , use the table below. It is data for the heights (inches) for Ms. Smith’s 4^th grade class.

Student	Height (inches)	Student	Height (inches)
1	47	11	53
2	47	12	54
3	47	13	55
4	49	14	56
5	50	15	59
6	51	16	59
7	51	17	60
8	52	18	60
9	52	19	60
10	52	20	91

1. The median height of the students is
   1. 42.32
   2. 52.50
   3. 54.45
   4. 58.35

2. The standard deviation (assume sample) of the students is
   1. 9.51
   2. 12.32
   3. 43.54
   4. 55.25

3. What is the z-score for the student who is 91 inches tall?
   1. Cannot be calculated from the data provided
   2. 0.00
   3. -3.76
   4. 3.76

4. Which measurement of central tendency is the best choice to describe the height of the students?
   1. Mode
   2. Median
   3. Mean
   4. Weighted Mean

Answer 1

Answer: The median height of the students is 52.5

Explanation: The median value is obtained in excel using the function =MEDIAN(). The screenshot is shown below,

Answer: The standard deviation (assume sample) of the students is 9.51

Explanation: The standard deviation is obtained in excel using the function =STDEV(). The screenshot is shown below,

Answer: What is the z-score for the student who is 91 inches tall is 3.76

Explanation: The z score is obtained using the formula,

Answer: Median is the best choice for the central tendency.

Explanation: Since the mean value is greater than the median value (because of an outlier data point => 91 inches), the distribution will be skewed hence the median will be preferred compared to the other central tendency.