Question

in C language only.

Write a program called gamecards.c that has a card game logic by comparing the cards from 4 people and calculating which player has the best card.

1. Every card must be represented by exactly two chars
representing a rank and a suit.

ranks: '2', '3', '4', '5', '6', '7', '8', '9', 'T', 'J', 'Q', 'K', 'A'. ('T' = 10)

Suits: 'H', 'D', 'S', 'C'.

7D represents the “7 of Diamond” etc..

2. Write a function called isRank(char c) which
calculate if the given character is one of the ranks. It would return a char with a value of 1 if the character is a valid rank and 0 if not.

Write a function called isSuit(char c) which calculate if the given character is one of the suits. It should return a char with a value of 1 if the character is a valid suit and 0 if not.
(Lowercase are not valid for both functions)

Answer 1

Please find the c program for the above problem:

#include<stdio.h>

//global variables to hold the value set by both the functions
char rankout, suitout;
int isRankthere, isSuitthere;

//declaration of both the methods
void isRank(char c);
void isSuit(char c);

int main()
{
   char rank, suit;
   printf("Make sure you enter the Rank and Suit in capital letters only..\n");
   printf("Enter the rank of the card\n");
   scanf("%c",&rank);
   getchar();
   printf("Enter the suit of the card\n");
   scanf("%c",&suit);
   getchar();
  
   // Calling both the methods
   isRank(rank);
   isSuit(suit);
  
   // Checking if the isRank method has returned true or false(0 or 1)
   if(isRankthere == 1)
   {
       printf("The rank is : %c\n",rankout);
   }
   else{
       printf("Rank is invalid\n");
   }
  
   // Checking if the isSuit method has returned true or false(0 or 1)
   if(isSuitthere == 1)
   {
       printf("The suit is : %c",suitout);
   }
   else{
       printf("Suit is invalid");
   }
}

//Method to check whether the rank exists or not
void isRank(char c)
{
   int i;
   char ranks[] = {'2','3','4','5','6','7','8','9','T','J','Q','K','A','\0'};
   for(i=0; i<sizeof(ranks); i++)
   {
       if(c == ranks[i]){
           isRankthere = 1;
           rankout = ranks[i];
       }
   }
}

//Method to check whether the suit exists or not
void isSuit(char c)
{
   int i;
   char suits[] = {'H','C','S','D','\0'};
   for(i=0; i<sizeof(suits); i++)
   {
       if(c == suits[i]){
           isSuitthere = 1;
           suitout = suits[i];
       }
   }
}

*The explanation has been given in comments.

Thanks!