Question

ONLY IN C LANGUAGE
Write a C program to print all the unique elements of an array.
Print all unique elements of an array

Enter the number of elements to be stored in the array: 4

Input 4 elements in the arrangement:
element [0]: 3
element [1]: 2
element [2]: 2
element [3]: 5

Expected output:
The only items found in the array are:
3 5

Answer 1

Please find the C code for the following:

Code:

#include <stdio.h>
int main()
{
int array[100],count=0,n=0;
  
//Prompt the user to enter the number of elements in the array
printf("Enter the number of elements to be stored in the array: ");
scanf("%d",&n);
  
//Accept the n elements as input from the user
printf("\nInput %d elements in the arrangement: \n",n);
for(int i=0;i<n;i++)
{
printf("element[%d]: ",i);
scanf("%d",&array[i]);
}
  
printf("The only items found in the array are:\n");
//Iterate through the loop elements and
for(int i=0;i<n;i++)
{
count=0;//Counter to count the occurences of the current element
//Iterate over the rest of all the elements again
for(int j=0;j<n; j++)
{
//Check if both numbers matches and they should not hold same index
if(array[i]==array[j] && i!=j)
count++;//Increment the count
}
//If count is 0, then it is unique. So print it
if(count==0)
printf("%d ",array[i]);
}
  
return 0;
}

Please check the compiled program and its output for your reference:

Output:

(I believe that I made the code simple and understandable. If you still have any query, Feel free to drop me a comment)

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