Question

In: Computer Science

In C language, Write a program called minishell that creates two child processes: one to execute...

In C language,

Write a program called minishell that creates two child processes:
one to execute 'ls -al' and the other to execute ‘grep minishell.c’.

After the forks, the original parent process waits for both child processes to finish before it terminates. The parent should print out the pid of each child after it finishes. The standard output of 'ls -al' process should be piped to the input to the 'grep minishell.c' process. Make sure you close the unnecessary open files for the three processes. The output should be the one line that includes the directory entry for minishell.c. You will need to call the source file minishell.c for this to work properly.

Please comment thoroughly so i can follow the logic.

Solutions

Expert Solution

ANSWER:--

GIVEN THAT:--

Answering the fist part of the question where the parent should wait for the two child process to finish

#include <stdio.h>
#include <fcntl.h>
#include <unistd.h>
#include <sys/types.h>
#include <sys/wait.h>

int main()
{
pid_t pid1, pid2;
int status;
// create the first child process

if ((pid1 = fork()) < 0) {
perror("error forking first child");
return -1;

}

if (pid1 == 0) {
// first child process - execute 'ls -al'
char *args[]={"/bin/ls","-al", NULL};
execvp(args[0], args);
}
//control does not get here since execvp has replaced the program image
// again fork
if ((pid2 = fork()) < 0) {
perror("error forking second child");
return -1;
}
if (pid2 == 0) {
// second child process execute 'grep main minishell.c'
char *args[]={"/bin/grep","main", "minishell.c", NULL};
execvp(args[0], args);
}
wait(&status);
fflush(stdout);
if (pid2 > 0 && pid1 > 0) {
printf("PID of the first child: %d\n", pid1);
printf("PID of the second child: %d\n", pid2);
}
return 0;
}

Now coming to the second part of the question the question seems little incorrect. Ideally to expect the desired output the grep pattern should be "grep minishell". Considering that the following code does the trick -

#include <stdio.h>
#include <fcntl.h>
#include <unistd.h>
#include <sys/types.h>
#include <sys/wait.h>

int main()
{
pid_t pid1, pid2;
int status;
int pipefds[2];
int ret;

// create a pipe where the child processes could communicate
ret = pipe(pipefds);

if (ret < 0) {
perror("error creating pipe");
return -1;
}


// create the first child process
if ((pid1 = fork()) < 0) {
perror("error forking first child");
return -1;
}
if (pid1 == 0) {
// first child process - execute 'ls -al'
char *args[]={"/bin/ls","-al", NULL};
// close the stdout of the process; redirect to the pipe write end
close(1);
dup2(pipefds[1], 1);
//close read end of pipe
close(pipefds[0]);
execvp(args[0], args);
}
//control does not get here since execvp has replaced the program image
// again fork
if ((pid2 = fork()) < 0) {
perror("error forking second child");
return -1;
}
if (pid2 == 0) {
// second child process execute 'grep main minishell.c'
char *args[]={"/bin/grep","minishell",NULL};
// redirect the stdin to the read end of pipe
close(0);
dup2(pipefds[0], 0);
//close write end of pipe
close(pipefds[1]);
execvp(args[0], args);
}
// close both pipefds in the parent since it never uses it
close (pipefds [0]);
close (pipefds [1]);
wait(&status);
fflush(stdout);
return 0;
}


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