Question

Complete the isScrambled() function to return True if stringA can be reordered to make stringB. Otherwise, return False. Ignore spaces and capitalization. You must use a list for this assignment. isScrambled( 'Easy', 'Yase' ) returns True isScrambled( 'Easy', 'EasyEasy' ) returns False isScrambled( 'eye', 'eyes' ) returns False isScrambled( 'abcdefghijklmnopqrstuvwxyz', 'zyxwvutsrqponmlkjihgfedcba' ) returns True isScrambled( 'Game Test', 'tamegest' ) returns True.

Answer 1

def isScrambled(stringA, stringB):
    stringA = stringA.lower() # make all the letters to lower case
    stringA = ''.join(stringA.split()) # remove spaces from the string

    stringB = stringB.lower() # make all the letters to lower case
    stringB = ''.join(stringB.split()) # remove spaces from the string

    a_list = list(stringA) # convert string to list
    a_list.sort() # sort the list

    b_list=list(stringB)# convert string to list
    b_list.sort() # sort the list

    return a_list==b_list # compare the list and return the result as the final answer


print(isScrambled('Easy', 'Yase'))
print(isScrambled('Easy', 'EasyEasy'))
print(isScrambled('eye', 'eyes'))
print(isScrambled('abcdefghijklmnopqrstuvwxyz', 'zyxwvutsrqponmlkjihgfedcba'))
print(isScrambled('Game Test', 'tamegest'))

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