Complete the isScrambled() function to return True if stringA can be reordered to make stringB. Otherwise,...

Complete the isScrambled() function to return True if stringA can be reordered to make stringB. Otherwise, return False. Ignore spaces and capitalization. You must use a list for this assignment. isScrambled( 'Easy', 'Yase' ) returns True isScrambled( 'Easy', 'EasyEasy' ) returns False isScrambled( 'eye', 'eyes' ) returns False isScrambled( 'abcdefghijklmnopqrstuvwxyz', 'zyxwvutsrqponmlkjihgfedcba' ) returns True isScrambled( 'Game Test', 'tamegest' ) returns True.

Expert Solution

def isScrambled(stringA, stringB):
    stringA = stringA.lower() # make all the letters to lower case
    stringA = ''.join(stringA.split()) # remove spaces from the string

    stringB = stringB.lower() # make all the letters to lower case
    stringB = ''.join(stringB.split()) # remove spaces from the string

    a_list = list(stringA) # convert string to list
    a_list.sort() # sort the list

    b_list=list(stringB)# convert string to list
    b_list.sort() # sort the list

    return a_list==b_list # compare the list and return the result as the final answer


print(isScrambled('Easy', 'Yase'))
print(isScrambled('Easy', 'EasyEasy'))
print(isScrambled('eye', 'eyes'))
print(isScrambled('abcdefghijklmnopqrstuvwxyz', 'zyxwvutsrqponmlkjihgfedcba'))
print(isScrambled('Game Test', 'tamegest'))

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venereology answered 3 hours ago

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