Consider a set of three standard six-sided dice (labelled with
pips). What is the probability that the total number of pips shown
on three dice thrown at the same time is 11? (I.e., P(11) = ?) What
is the probability that the total is 12? (I.e., P(12) = ?)
What is the fallacy in the following argument?
The number 11 occurs in six ways: (1,4,6), (2,3,6), (1,5,5),
(2,4,5), (3,3,5), (3,4,4). The number 12 also occurs in six ways:
(1,5,6), (2,4,6), (3,3,6), (2,5,5), (3,4,5), (4,4,4). Therefore the
two numbers, 11 and 12, should be equally probable.