In: Math
Consider a six-sided fair dice. Complete the following tables for this die:
Number on the dice |
Number of times it appears on the dice |
Relative frequency of seeing that number |
1 |
||
2 |
||
3 |
||
4 |
||
5 |
||
6 |
||
Total |
This is the entire question, does not say how many times the dice is thrown
This is a six sided fair die having numbers 1 through 6, each value appearing only once, since this is a fair die.
Hence the number of times 1 appears on the die face is 1, similarly 2,3,4,5,6 appear once each on one of the faces.
There are a total of 6 numbers printed on the die/there are 6 faces.
The relative frequency of any number on the die is (number of times it appears on the die)/(Total number faces on the die)
That means, the relative frequency of 1 is 1/6. Similarly the relative frequencies of the rest of the numbers are 1/6 each.
The table now can be filled
Number on the dice | Number of times it appears on the dice | Relative frequency of seeing that number |
1 | 1 | 0.1667 |
2 | 1 | 0.1667 |
3 | 1 | 0.1667 |
4 | 1 | 0.1667 |
5 | 1 | 0.1667 |
6 | 1 | 0.1667 |
Total | 6 | 1 |
In other words, if X is the number that the die lands on face up, when rolled, the probability distribution of X is
Number rolled (x) | P(x) |
1 | 0.1667 |
2 | 0.1667 |
3 | 0.1667 |
4 | 0.1667 |
5 | 0.1667 |
6 | 0.1667 |
Or the probability that 1 is rolled on any given roll of this die is 1/6.
similarly the probability that 2 is rolled is 1/6 and so on.