Question

In: Math

All but the "face" cards (Kings, Queens, Jacks) have been removed from a regular deck of...

All but the "face" cards (Kings, Queens, Jacks) have been removed from a regular deck of 52 playing cards

Draw two cards at random, without replacement. What is the probability that both cards are "Spades"? (Write answer as a fraction reduced to lowest terms) ___________

Based on your answer above, what are the Odds Against both cards being "Spades"? __________

Now draw a third card, again without replacement. What is the probability that this third card is a "Spade" GIVEN that NEITHER of the first two cards drawn are "Spades"? _____________

What would be your answer to the first question asked in this problem if the drawing had been done WITh replacement? ____________

Solutions

Expert Solution

There are 52 cards & 12 face cards in a deck . Now, if we remove 12 face cards, the remaining cards are 40

1. 2 cards are removed in random without replacement from 40 cards. This can be done in ways.

Now, there are 13 spade cards in a deck of 52 cards. When we removed the 3 face cards, there are only 10 cards remaining. Out of these 10 cards, 2 are to selected , which can be done in ways.

Therefore, the probability that both cards are spade =   / = 45 / 780 = 0.058

2. There are 40 cards in total, out of which 10 cards are spade and the remaining 30 cards are non spade.

Now, the Odds Against both cards being "Spades" =    / = 0.5577

3. There are 10 spades & 30 non spades. Now, when 2 cards are already drawn & they both are non spades, we have remaining 28 non spades and 10 spades in a total of 38 cards.

Now, this 1 spade card has to be selected out of 10 in ways.

In case of sample space, 1 card in general can be selected from 38 cards in ways.

Therefore, probability that this third card is a "Spade" GIVEN that NEITHER of the first two cards drawn are "Spades" is given by,

P = / = 0.2631

4. There are 40 cards in a deck out of which 10 are spade.

When we pick the 1st card, the probability of it being spade = 10 / 40

When we pick the 2nd card, the probability of it being spade = 10 / 40

Therefore, their combined probability = 10/40 * 10/40 = 0.0625.

Hope I answered your query. DO like and comment, if you like my answer.


Related Solutions

11.There are twelve face cards (the kings, queens, and jacks). What is the probability of picking...
11.There are twelve face cards (the kings, queens, and jacks). What is the probability of picking four cards and getting at least one queen? 12.I remove the ace of spades from a deck of cards. In this modified deck, are kings and hearts independent events? Please explain.
In how many ways can 3 aces, 3 kings, 3 queens, and 3 jacks be selected...
In how many ways can 3 aces, 3 kings, 3 queens, and 3 jacks be selected from a standard deck of cards if cards are drawn without replacement?
Consider a reduced deck where all cards 2, 3, 4, and 5 (16 cards) are removed....
Consider a reduced deck where all cards 2, 3, 4, and 5 (16 cards) are removed. In a game of five card draw find the number of ways to draw one pair, two pair, three of a kind, straight, flush, full house, four of a kind, straight flush, and royal flush.
A card is selected from a regular deck of cards.  Count the number of outcomes with:  a) a...
A card is selected from a regular deck of cards.  Count the number of outcomes with:  a) a king or a queen, b) red and ace, c) spade and heart, and d) odd or less than five.
Have a regular deck of cards with no jokers (13 cards per suit, 4 suits) giving...
Have a regular deck of cards with no jokers (13 cards per suit, 4 suits) giving 52 cards. Suppose we draw 5 card hand, so 5 cards without replacement. What is the probability of getting a royal flush but where the cards ordered by rank have alternate color? That is, order the cards as 10,J,Q,K,A and then check to see they have alternate colour. Note in a proper royal flush, it is all the one suit, but we have changed...
You draw cards from a standard deck of 52 playing cards. There are 12 “face cards”...
You draw cards from a standard deck of 52 playing cards. There are 12 “face cards” in the deck (J, Q, or K). Let X be the number of drawings (with replacement) it takes until you get your first face card. Let Y be the number of drawings (with replacement) it takes until you get your fifth face card. Let Z be the number of face cards removed if you draw 10 cards without replacement. (a) Calculate P(X = 5)....
52 cards in a deck choose 5 What is the probability of choosing 4 kings and...
52 cards in a deck choose 5 What is the probability of choosing 4 kings and one other card. what is the probability of choosing one king and 4 other cards with the same number?
Here is a table showing all 52 cards in a standard deck. Face cards Color Suit...
Here is a table showing all 52 cards in a standard deck. Face cards Color Suit Ace Two Three Four Five Six Seven Eight Nine Ten Jack Queen King Red Hearts A ♥ 2 ♥ 3 ♥ 4 ♥ 5 ♥ 6 ♥ 7 ♥ 8 ♥ 9 ♥ 10 ♥ J ♥ Q ♥ K ♥ Red Diamonds A ♦ 2 ♦ 3 ♦ 4 ♦ 5 ♦ 6 ♦ 7 ♦ 8 ♦ 9 ♦ 10 ♦ J...
Here is a table showing all 52 cards in a standard deck. Face cards Color Suit...
Here is a table showing all 52 cards in a standard deck. Face cards Color Suit Ace Two Three Four Five Six Seven Eight Nine Ten Jack Queen King Red Hearts A ♥ 2 ♥ 3 ♥ 4 ♥ 5 ♥ 6 ♥ 7 ♥ 8 ♥ 9 ♥ 10 ♥ J ♥ Q ♥ K ♥ Red Diamonds A ♦ 2 ♦ 3 ♦ 4 ♦ 5 ♦ 6 ♦ 7 ♦ 8 ♦ 9 ♦ 10 ♦ J...
In this game, you will play in pairs with a single deck of cards (face cards...
In this game, you will play in pairs with a single deck of cards (face cards removed). Aces count as ones and all numbered cards count at face value. Players take turns flipping over two cards and finding the product. Regardless of who flipped the cards, Player 1 always gets one point if the product is even, and Player 2 always gets one point if the product is odd. Continue playing until one player reaches 20 points. Would you rather...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT