Question

Draw a flowchart and pseudocode that accepts three numbers from a user and displays a message if the sum of any two numbers equals the third.

Make a working version of this program in Python.

Answer 1

Dear Student ,

As per the requirement submitted above , kindly find the below solution.

Flow chart :

Demonstration :

Here a new python program with name "main.py" is created, which contains following code.

main.py :

#asking user to enter number1
number1=int(input("Enter first number:"))
#asking second number
number2=int(input("Enter second number:"))
#asking third number
number3=int(input("Enter third number:"))
#checking sum of any two number with third one
if((number1+number2)==number3):
#if sum of number1 and number2 are equal to number3 then
print("sum of "+str(number1)+" and "+str(number2)+" are equal to "+str(number3))
elif((number2+number3)==number1):
#if sum of number3 and number2 are equal to number1 then
print("sum of "+str(number2)+" and "+str(number3)+" are equal to "+str(number1))
elif((number1+number3)==number2):
#if sum of number1 and number3 are equal to number2 then
print("sum of "+str(number1)+" and "+str(number3)+" are equal to "+str(number2))
else:
print("sum of any two numbers are not equal to third one")

======================================================

Output : Compile and Run main.py to get the screen as shown below

Screen 1 :main.py, screen when sum of any two number is not equal to third one

Screen 1 :main.py, screen when sum of any two number is equal to third one

NOTE : PLEASE FEEL FREE TO PROVIDE FEEDBACK ABOUT THE SOLUTION.