Question

Consider a list called A:

A = [-6, 10, 100, 5, -20, 1000, 9, -15]

Make a for loop that iterates over A and:

• If number is negative, print the square of the number.
• if number is positive but less than or equal to 100, print the number itself.
• if number is positive but greater than 100, print 0.

Answer 1

HELLO

AS YOU HAVE NOT SPECIFIED ANY LANGUAGE I AM ADDING SOLUTION WITH OUTPUT IN PYTHON AND C

PLEASE GO THROUGH IT AND IF YOU HAVE ANY DOUBT PLEASE FEEL FREE TO ASK IN COMMENT

AND IF THIS HELPS YOU PLEASE GIVE UPVOTE

CODE (C)

#include <stdio.h>

int main()
{
    //DECLARING ARRAY WITH GIVEN LIST
    int A[8]={-6,10,100,5,-20,1000,9,-15};
    int i;
    //ITERATING THROUGH LOOP
    for(i=0;i<8;i++)
    {
        int display = 0;
        //IF ELEMENT IS NEGATIVE
        if(A[i]<0)
            display = A[i]*A[i];
        //IF ELEMENT IS POSITIVE AND LESS THAN OR EQ TO 100
        else if(A[i]<=100)
            display = A[i];
        //ELSE ELEMENT IS GREATER THAN 100
        printf("%d  ",display);
    }
    return 0;
}

OUTPUT (C):

CODE (PYTHON)

def printNum(list):
    #ITERATING THROUGH LOOP
    for i in list:
        display =0
        #IF ELEMENT IS NEGATIVE
        if(i<0):
            display = i*i
        #IF ELEMENT IS POSITIVE AND LESS THAN OR EQ TO 100
        elif(i<=100):
            display = i
        #ELSE ELEMENT IS GREATER THAN 100
        print(display)
        
list = [-6,10,100,5,-20,1000,9,-15]
printNum(list)

OUTPUT (PYTHON)