Question

C++

1) Given Arr[10] = {7, 9, 13, 15, 16, 10, 12, 5, 20, 27}

Write a program to count number of EVEN and ODD items. Do a screen output of your result.

2) Given Arr[10] = {7, 9, 13, 15, 16, 10, 12, 5, 20, 27}

Write a program to construct array ODD[] and EVEN[] from Arr[10] as you realize ODD[] consists of odd number and EVEN[] consists of even number.

Answer 1

#include<bits/stdc++.h>
using namespace std;

int main(){
  int n; // total number of elements in the array
  cin >> n;
  int arr[n]; //defining array of size n
  int oddCount = 0, evenCount = 0;
  for(int i = 0; i<n; i++){
    cin >> arr[i];
    if(arr[i]%2 == 0) // checking if number is even
    {
      evenCount = evenCount +1; //increasing even count
    }
    else{ // checking for odd numbers
      oddCount = oddCount + 1; // increasing odd count
    }
  }
  cout << "Total number of even numbers are " << evenCount << " and total number of odd numbers are " << oddCount << endl;
  int even[evenCount]; // array of even numbers only
  int odd[oddCount];  // array of odd numbers only
  //Question two starts from here
  
  int j = 0, k = 0; // iterators 
  for(int i = 0; i < n; i++){
    if(arr[i]%2 == 0) // checking if number is even
    {
      even[j++] = arr[i]; // storing even numbers in even array
    }
    else{ // checking for odd numbers
      odd[k++] = arr[i]; // storing odd numbers in odd array
    }
  }
  cout << "Even numbers array : ";
  for(int i = 0 ; i<evenCount; i++){ // dispalying even numbers array
    cout << even[i] << " ";
  }
  cout << "\nOdd numbers array : ";
  for(int  i = 0; i<oddCount; i++){ //displaying odd numbers array
    cout << odd[i] << " ";
  }
}

output will look like below image

i have done both questions combined and added comments for better understanding. i hope it will help you.

for any more doubt comment below.