Question

Write a Python Program

Continue to ask the user to enter a POSITIVE number until they type DONE to quit.

• The program should DOUBLE each of the digits in the number and
  display the original entry AND the SUM of the doubled digits.
  
• Hint: Use the // and % operators to accomplish this.
  
• Print the COUNT of entries that were invalid
  
• Examples: if the user enters 93218, the sum of the doubled digits is 18+6+4+2+16 = 46.
  

User Entry	Output	Explanation
46	Original Number: 46 Sum of Doubled Digits: 20	4*2 + 6*2 = 8 + 12 = 20
93218	Original Number: 93218 Sum of Doubled Digits: 46	9*2 + 3*2 + 2*2 + 1*2 + 8*2 = 18    +    6   + 4    +    2   + 16 = 46
-89	Invalid Entry
567	Original Number: 567 Sum of Doubled Digits: 36	5*2 + 6*2 + 7*2 = 10+12+14 =36
-2	Invalid Entry
DONE	Number of Invalid Entries: 2

Next, continue to ask the user to enter a positive number until they type DONE

• Display each number in reverse order.
  NOTE: You may NOT use lists and the sort method for this problem!
  
• Examples:

User Entry	Output
753	357
8976	6798
2	2
123456	654321
DONE	Program Ended

Answer 1

1 ans:

invalid_count=0

while(True):

n=input("Enter positive Number:")

if(n=="DONE"):

print("Number of invalid Entries:",invalid_count)

break

else:

n=int(n)

if(n<0):

print("Invalid Entry")

invalid_count+=1

else:

n=str(n)

s=0

for i in n:

s=s+int(i)*2

print("Original Number:{}\nSum of Double Digits:{}".format(n,s))

#source code:

#2 ans:

while(True):

n=input("")

if(n=="DONE"):

print("Program Ender")

break

else:

n=int(n)

if(n>0):

n=str(n)

print(n[::-1]) #string slicing

else:

print("Invalid Entry")

#another way

while(True):

n=input("")

if(n=="DONE"):

print("Program Ended")

break

else:

n=int(n)

if(n>0):

n=str(n)

out=""

for i in range(len(n)-1,-1,-1):

out=out+n[i]

print(out)

else:

print("Invalid Entry")