In: Chemistry

50lbs of gas with the specific gavity of .88(treat as real gas) is in a tank at p=1384 psig and at T=320F what is volume of the tank in ft^3 This question is in oilfield units

mass = 50 lbs

1 lb = 453.59 g

50 lbs = 453.59 x 50

= 22679.5 g

pressure = 1384 psi

1 psi = 0.068 atm

1384 psi = 0.068 x 1384

= 94.112 atm

T = 320 F

320 F = 160oC = 433 K

specific gravity = density of substance / density of water

0.88 = density of substance / 1

denity = 0.88 g/ cm^3

volume = mass / density

= 22679.5 / 0.88

= 25772.15 cm^3

1 cm^3 = 3.53 x 10^-5 ft^3

25772.15 cm^3 = 25772.15 x 3.53 x 10^-5 ft^3

= 0.909 ft^3

**volume of the tank = 0.909 ft^3**

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