Gas is confined in a tank at a pressure of 11.5 atm and a temperature of...

Gas is confined in a tank at a pressure of 11.5 atm and a temperature of 22.0°C. If two-thirds of the gas is withdrawn and the temperature is raised to 60.0°C, what is the pressure of the gas remaining in the tank?

Expert Solution

The final moles of the gas is,

N₂ = (1/3)N₁

Use the ideal equation to find the pressure of the gas.

P2/P1 =(N₂/N₁) *(T₂/T₁)

Thus, the final pressure of the gas is,

P2 =(N₂/N₁) *(T₂/T₁)*P1

=(1/3)* [(60+273) K / (22 + 273) K] (11.5 atm)

= 4.327 atm

= 4.3 atm

genius_generous answered 2 years ago

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