Question

In: Chemistry

Using a table of standard electrode potentials, decide which of the following statements is completely true....

Using a table of standard electrode potentials, decide which of the following statements is completely true.

A. Cu2+ can oxidize H2, and Fe can reduce Mn2+ .

B. Ni2+ can oxidize Cu2+, and Fe2+ can reduce H+ .

C. Fe2+ can oxidize H2, and Fe2+ can reduce Au3+ .

D. Br2 can oxidize Ni, and H2 can reduce Mn2+ .

E. H + can oxidize Fe, and Ni can reduce Br2.

Answer: E.. but why? can you explain why A-D are incorrect and why E is right. I know it has something to do with how they are positioned on the standard reduction potential list, but I dont understand the concept, which I will need to know for my exam. thank you!

Expert Solution

E is correct option.

Explaination: H⁺ can oxidize Fe because the oxidation potential of Fe is more than H₂.

Fe Fe²⁺ + 2e- E⁰ = 0.44V

H H⁺ + e^- E⁰ = 0V

also, Ni can reduce Br₂ because reduction potential of Ni is more than Br₂.

Ni²⁺ + 2e^- Ni E⁰ = -0.25V

2Br ^- Br₂ + 2e^- E⁰ = -1.087V

why A & D are incorrect?

Explaination: oxidation potential of Fe is less than Mn²⁺ so Fe can not reduce Mn²⁺

Fe + 2e^- Fe²⁺ E⁰ = 0.44V

Mn + 2e^- Mn²⁺ E⁰ = 1.185V

and,

Br₂ can not oxidize Ni because oxidation potential of Br₂ is less than Ni.

2Br^- Br₂ + 2e^- E⁰ = -1.0873V

Ni²⁺ + 2e^- Ni E⁰ = -0.25V

queen_honey_blossom answered 3 weeks ago

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