In: Statistics and Probability
The Bobs want to know if Apple computers are better than Microsoft. Corporations using the Bobs consulting agency are surveyed for their employees’ use of Apple versus Microsoft computers and their level of productivity. The data is summarized below. Use α = .01.
** I need to see work for FULL points. Please show your work on scrap paper!!**
Productivity | Apple | Microsoft | Total |
Bad | 66 | 23 | 89 |
Average | 62 | 74 | 136 |
Great | 71 | 15 | 86 |
Total | 199 | 112 | 311 |
What is your decision?
Reject the Null
Fail to Reject the Null
What is your interpretation of the finding (i.e. the conclusion)?
Chi-Square Test | |||||||
Observed Frequencies | |||||||
Apple | Microsoft | Total | |||||
Bad | 66 | 23 | 89 | ||||
Average | 62 | 74 | 136 | ||||
Great | 71 | 15 | 86 | ||||
Total | 199 | 112 | 311 | ||||
Expected frequency of a cell = sum of row*sum of column / total sum | |||||||
Expected Frequencies | |||||||
Apple | Microsoft | Total | |||||
Bad | 199*89/311=56.949 | 112*89/311=32.051 | 89 | ||||
Average | 199*136/311=87.023 | 112*136/311=48.977 | 136 | ||||
Great | 199*86/311=55.029 | 112*86/311=30.971 | 86 | ||||
Total | 199 | 112 | 311 | ||||
(fo-fe)^2/fe | |||||||
Bad | 1.4386 | 2.5562 | |||||
Average | 7.1950 | 12.7840 | |||||
Great | 4.6353 | 8.2359 | 0.7416 |
Chi-Square Test Statistic,χ² = Σ(fo-fe)^2/fe =
36.845
Level of Significance = 0.01
Number of Rows = 3
Number of Columns = 2
Degrees of Freedom=(#row - 1)(#column -1) = (3- 1 ) * ( 2- 1 )
= 2
p-Value = 0.0000
Decision: p-value < α , Reject
Ho
decision: reject the null
conclusion: there is enough evidence to conlcude that Apple computers are better than Microsoft