Question

In: Statistics and Probability

The Bobs want to know if Apple computers are better than Microsoft. Corporations using the Bobs...

The Bobs want to know if Apple computers are better than Microsoft. Corporations using the Bobs consulting agency are surveyed for their employees’ use of Apple versus Microsoft computers and their level of productivity. The data is summarized below. Use α = .01.

** I need to see work for FULL points. Please show your work on scrap paper!!**

Productivity Apple Microsoft Total
Bad 66 23 89
Average 62 74 136
Great 71 15 86
Total 199 112 311

What is your decision?

Reject the Null

Fail to Reject the Null

What is your interpretation of the finding (i.e. the conclusion)?

Solutions

Expert Solution

Chi-Square Test
Observed Frequencies
Apple Microsoft Total
Bad 66 23 89
Average 62 74 136
Great 71 15 86
Total 199 112 311
Expected frequency of a cell = sum of row*sum of column / total sum
Expected Frequencies
Apple Microsoft Total
Bad 199*89/311=56.949 112*89/311=32.051 89
Average 199*136/311=87.023 112*136/311=48.977 136
Great 199*86/311=55.029 112*86/311=30.971 86
Total 199 112 311
(fo-fe)^2/fe
Bad 1.4386 2.5562
Average 7.1950 12.7840
Great 4.6353 8.2359 0.7416

Chi-Square Test Statistic,χ² = Σ(fo-fe)^2/fe =   36.845  
      
Level of Significance =   0.01  
Number of Rows =   3  
Number of Columns =   2  
Degrees of Freedom=(#row - 1)(#column -1) = (3- 1 ) * ( 2- 1 ) =   2  
      
p-Value =   0.0000   
Decision:    p-value < α , Reject Ho  

decision: reject the null

conclusion: there is enough evidence to conlcude that Apple computers are better than Microsoft


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