In: Finance
In addition to the five factors discussed in the chapter,
dividends also affect the price of an option. The Black–Scholes
option pricing model with dividends is:
  
C=S × e−dt × N(d1) − E × e−Rt × N(d2)C=S × e−dt × N(d1) − E × e−Rt × N(d2)
d1= [ln(S  /E ) +(R−d+σ2 / 2) × t ] (σ − t√) d1= [ln(S  /E ) +(R−d+σ2 / 2) × t ] (σ − t) 
d2=d1−σ × t√d2=d1−σ × t
  
All of the variables are the same as the Black–Scholes model
without dividends except for the variable d, which is the
continuously compounded dividend yield on the stock.
  
A stock is currently priced at $81 per share, the standard
deviation of its return is 50 percent per year, and the risk-free
rate is 4 percent per year, compounded continuously. What is the
price of a call option with a strike price of $77 and a maturity of
six months if the stock has a dividend yield of 2 percent per year?
(Do not round intermediate calculations and round your
answer to 2 decimal places, e.g., 32.16.)
  
Price of call option  
| 
 S' = Stock price =  | 
 81  | 
| 
 D = Dividend yield =  | 
 4.00%  | 
| 
 S = Stock price ajusted = S'*exp(D*T) = 81*exp(-2%*0.5) =  | 
 80.194037  | 
| 
 K = Strike price =  | 
 77  | 
| 
 r = rate =  | 
 4%  | 
| 
 e = exponential value = exp(.) =  | 
 2.71828183  | 
| 
 t = time =  | 
 0.5  | 
| 
 s = standard deviation or volatility =  | 
 50%  | 
| 
 * N(d1) is Normal distribution probability value  | 
|
| 
 * N(d2) is Normal distribution probability value  | 
|
| 
 Use normal distribution table  | 
d1 = (Ln(S/(K*exp(-r*t))+0.5*s^2*t)/(s*t^0.5)
=(LN(80.194037/((77*EXP(-0.04*0.5))))+0.5*50%^2*0.5)/(50%*0.5^0.5)
d1 = 0.348303 Hence, N(d1) =0.6361937
d2 = d1 - (s*t^0.5)
d2 = 0.348303-(50%*0.5^0.5)
d2 = -0.005250391 Hence, N(d2) =0.497905407
C = S*N(d1)-K*exp(-r*t)*N(d2)
=80.194037*0.6361937-77*exp(-4%*0.5)*0.497905
C = 13.44
Value of call option = 13.44