Question

C++

Write the implementation of the function concatenateIntArrays. This function receives 4 parameters in the following order:

1. An array of integer values (array1).
2. An integer representing the size of array1 (size1).
3. An array of integer values (array2).
4. An integer representing the size of array2 (size).

The function creates a dynamic array of integers of size size1+size2 to store all the values in array1, followed by all the values in array2. The function returns the pointer used to create the dynamic array of integers.

Example:

Given the two arrays of integers:

• array1[]={1,2,3,4,5};
• array2[]={6,7};
• size1 = 5;
• size2 = 2;

The dynamic array of integers created by your function must be and array size 7 with the following values:

1,2,3,4,5,6,7

Answer 1

#include <iostream>
using namespace std;
void concatenateIntArrays(int array1[],int sizea1,int array2[],int sizea2){
int n = sizea1 + sizea2;
int array3[n];
for(int i=0;i<sizea1;i++){
array3[i] = array1[i];
}
for(int i=0;i<sizea2;i++){
array3[sizea1+i] = array2[i];
}
//DYNAMIC ARRAY
int *arr = new int(n);
for(int i=0;i<n;i++){
arr[i] = array3[i];
cout<<arr[i]<<",";
}
}
int main() {
int array1[] = {1,2,3,4,5};
int array2[] = {6,7};
int sizea1 = sizeof(array1)/sizeof(array1[0]);
int sizea2 = sizeof(array2)/sizeof(array1[0]);
// cout<<sizea1<<" "<<sizea2<<endl;
concatenateIntArrays(array1,sizea1,array2,sizea2);
}