Question

In: Statistics and Probability

Could we write an equation to estimate Aron’s bowling score based on his Brennivín consumption?

Aron
1 2 3 4 Average

8/6/2017

90 138 118 105 112.8
8/19/2017 162 101 120 145 132
9/16/2017 101 129 132 111 118.3
Average 117.7 122.7 123.3 120.3 121
Mjorgan
1 2 3 4 Average
8/6/2017 115 88 94 102 99.8
8/19/2017 89 75 77 90 82.8
9/16/2017 74 110 117 90 97.8
Average 92.7 91 96 94 93.4

Mjorgan drinks a simple Egils beer while bowling. But Aron drinks the traditional Viking beverage Brennivín ("Black death") which has a particularly high alcohol content. As of his first game, he has not had any Brennivín, but after that he drinks about one per game bowled. Is there a correlation between his score and the number of Brennivín he has drank each night? (You might want to carefully construct a data table showing how many he has had at each point on each night, and his score. Note that three nights are presented here.) How would we interpret this correlation?

4. Could we write an equation to estimate Aron’s bowling score based on his Brennivín consumption? Run the statistical test to create this equation, diagnose it, and then interpret its findings and its accuracy. Is this a particularly good model?  

Solutions

Expert Solution

Yes, As per the data given for 3 nights, there is positive correlation between number of Brennivín and his score. However correlation is not very high.
Out of 3 instances, one is showing negative correlation. Similarly if you can check the correlarion with average score of each drink, there is high positive correlation.

Day 1 Day 2 Day 3 Average
1 90 162 101 118
2 138 101 129 123
3 118 120 132 123
4 105 145 111 120
Correlation 16% -15% 29% 44%
Days Score # of Brennivin
1 90 1
1 138 2
1 118 3
1 105 4
2 162 1
2 101 2
2 120 3
2 145 4
3 101 1
3 129 2
3 132 3
3 111 4
Score is dependent variable and # of Brennivin is independent variable.
It is not a good model. R Square is just 4% it means that variablity in score is not completely explained by number of drinks. Again the p-value is very high. So we can conlcude that there might be another factors which are responsible for scores.
SUMMARY OUTPUT
Regression Statistics
Multiple R 0.048158058
R Square 0.002319199
Adjusted R Square -0.097448882
Standard Error 22.01529771
Observations 12
ANOVA
df SS MS F Significance F
Regression 1 11.26666667 11.26666667 0.023245898 0.881851741
Residual 10 4846.733333 484.6733333
Total 11 4858
Coefficients Standard Error t Stat P-value Lower 95%
Intercept 118.8333333 15.5671663 7.633587965 1.77114E-05 84.14752543
# of Brennivin 0.866666667 5.684325427 0.152466054 0.881851741 -11.79879961
Equation --> Score = 118.83 + number of Brennivin

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