Question

Print the following two patterns using nested loops. Pattern 1 13579 13579 13579 13579 Pattern 2 #####1 ####12 ###123 ##1234 #12345

Answer 1

Pattern 1:

#include<bits/stdc++.h>

using namespace std;

int main()
{
    int count=1;                   //initializing count as 1
    for(int i=1;i<=4;i++){        //numbers of rows
        for(int j=1;j<=5;j++){   //number of columns 
            cout<<count;        //printing digits in row
            count=count+2;     //adding 2 
        }
            cout<<endl;       //go to new line
            count=1;         //make count again 1 for 2nd row
    }
}

Pattern 2:

#include<bits/stdc++.h>

using namespace std;

int main()
{
    int count=1;                //initializing count as 1
    for(int i=1;i<=5;i++){      //for loop for row
        for(int j=1;j<=6;j++){  //for loop for column
            
             if(j<=6-i){        
            cout<<"#";
            }
            else
            {
            cout<<count++;        
            }   
        }
            cout<<endl;
            count=1;     
    }
    
}