Question# 2 –A Max 7x 1 + 5x 2 S.t x 2 < 6 (1) ...

Question# 2 –A

Max 7x 1 + 5x 2
S.t x 2 < 6 (1)

3x 1 + 2x 2 < 18 (2)

x 1 + x 2 < 8 ( 3)

x 1 > 0 and x 2 > 0

Question #2-B IF we increase s.t two 12 hours & three 8 hours (MAX profit)

Expert Solution

Solution:

2A:

2B:

The constraint 2 will increase by 12 and constraint 3 will increase by 8.

Hence, the new solution will be,

keosha answered 2 months ago

\int \frac{x^6+5x^4+4x-3}{\left(x^2+3x+5\right)\left(x^2+7x+12\right)}dx

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