Let x0< x1< x2. Show that there is a unique polynomial P(x) of degree at most...

Let

x0< x1< x2. Show that there is a unique polynomial P(x) of degree at most 3 such that

P(xj) =f(xj) j= 0,1,2, and P′(x1) =f′(x1) Give an explicit formula for P(x).

maybe this is a Hint using the Hermit Polynomial:

P(x) = a0 +a1(x-x0)+a2(x-x0)^2+a3(x-x0)^2(x-x1)

Expert Solution

Colby Messinger answered 2 years ago

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Question

Let x0< x1< x2. Show that there is a unique polynomial P(x) of degree at most...

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Expert Solution

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