Input a phrase from the keyboard. If the last letter in the phrase is "a" or...

Input a phrase from the keyboard. 
If the last letter in the phrase is  "a" or "e" (uppercase or lowercase) then output the last letter 3 times.
ELSE
If the first letter in the phrase is either "i", "o", or "u" (uppercase or lowercase) then output the length of the phrase
In all other cases print "no vowel"

Code language is java

Solutions

Expert Solution

Solution:-

Java Code:-

import java.util.*;
// Main class
public class Main
{
// main method
   public static void main(String[] args) {
   System.out.print("Enter the phrase: ");
   // Instantiate object of Scanner class
   Scanner sc = new Scanner(System.in);
   // Taking user input of phrase
   String phrase = sc.nextLine();
   // Computing last index of phrase
   int len = phrase.length()-1;
   // In case last letter in the phrase is "a" or "e" (uppercase or lowercase)
   if( (phrase.charAt(len) == 'a') || (phrase.charAt(len) == 'e') ||
   (phrase.charAt(len) == 'A') || (phrase.charAt(len) == 'E') )
   {
   // Prinitng last letter 3 times
   System.out.println(phrase.charAt(len));
   System.out.println(phrase.charAt(len));
   System.out.println(phrase.charAt(len));
   }
   // In case last letter in the phrase is "i", "o", or "u" (uppercase or lowercase)
   else if( (phrase.charAt(0) == 'i') || (phrase.charAt(0) == 'o') || (phrase.charAt(0) == 'u') ||
(phrase.charAt(0) == 'I') || (phrase.charAt(0) == 'O') || (phrase.charAt(0) == 'U') )
{
// Prinitng length of phrase
System.out.println(phrase.length());
}
// In all other cases
else{
System.out.println("no vowel");
}

   }
}

Code snapshot:-

Output snapshot:-

venereology answered 2 hours ago

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