In: Math
Use Minitab to answer the questions. Make sure to copy all output from the Minitab:
1. Followings Tables shows previous 11 months stock market returns.
Date |
Monthly SP500 Return |
Monthly DJIA Return |
12/7/2007 |
-0.8628 |
-0.7994 |
1/8/2008 |
-6.1163 |
-4.6323 |
2/8/2008 |
-3.4761 |
-3.0352 |
3/8/2008 |
-0.5960 |
-0.0285 |
4/8/2008 |
4.7547 |
4.5441 |
5/8/2008 |
1.0674 |
-1.4182 |
6/8/2008 |
-8.5962 |
-10.1937 |
7/8/2008 |
-0.9859 |
0.2468 |
8/8/2008 |
1.2191 |
1.4548 |
9/8/2008 |
-9.2054 |
-6.0024 |
10/8/2008 |
-16.8269 |
-4.8410 |
Ho : µ1 = µ2
Ha : µ1 ≠ µ2
Ho : σ21 = σ22
Ha : σ21 ≠ σ22
6) Perform the following hypothesis test
Ho : σ21 ≤ σ22
Ha : σ21 > σ22
1) We have to test ,
Ho : µ1 = µ2
Ha : µ1 ≠ µ2
Calculation using Minitab:-
Two-sample T for SP vs DJIA
N Mean StDev SE Mean
SP 11 -3.60 6.13 1.8
DJIA 11 -2.25 4.05 1.2
Difference = μ (SP) - μ (DJIA)
Estimate for difference: -1.36
95% CI for difference: (-6.03, 3.32)
T-Test of difference = 0 (vs ≠): T-Value = -0.61
P-Value = 0.548 DF = 17
Result:- Here p-value is greater than alpha=0.05. Hence we accept the null hypothesis.
Hence we say that, population mean of SP500 is same as population mean of DJIA . I.e. µ1 = µ2
2) We have to check,
Ho : σ21 = σ22
Ha : σ21 ≠ σ22
Calculation using Minitab :-
Minitab output,
Method
Null hypothesis All variances are equal
Alternative hypothesis At least one variance is different
Significance level α = 0.05
95% Bonferroni Confidence Intervals for Standard
Deviations
Sample N StDev CI
SP 11 6.13058 (4.08177, 11.7826)
DJIA 11 4.05017 (2.69662, 7.7842)
Individual confidence level = 97.5%
Tests
Test
Method Statistic P-Value
F 2.29 0.207
Result :-
Here p-value is greater than alpha=0.05. Hence we accept the null hypothesis.
Hence we say that, population variance of SP500 is equal as population variance of DJIA . i.e. σ21 = σ22