A mass, m=1.4 kg of negligible size, is attached at the end of a uniform rod...

A mass, m=1.4 kg of negligible size, is attached at the end of a uniform rod of length L= 0.99 mm which has mass M= 1.9 kg . What is the moment of inertia of this arrangement if it is to rotate at an axis located at a distance 0.39*L from the end of the rod opposite to the mass, m? (At approximately the point marked with an 'X'.)

Calculate the moment of inertia of the rod-mass system given that the moment of inertia of a rod about the center of mass is I=(1/12)* M*L^2

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genius_generous answered 2 hours ago

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