Use the following description to answer question 9. The mean height of American women in their...

Use the following description to answer question 9. The mean height of American women in their early twenties is about 64.5 inches and the SD is about 2.5 inches. The mean height of men the same age is about 68.5 inches, with a SD about 2.7 inches. It is also known that the correlation between the heights of husbands and wives is about r = +.50. Women (Y) Men (X) 66 70 64 68 62 66 66 71 65 67 67 68 62 69 66 69 65 69 63 67 68 70

9. Use Excel to obtain the values for the following (A) What is the value of the slope for the regression equation when predicting women’s heights from men’s heights? (B) Obtain the value of the y intercept. (C) Provide an interpretation of the y intercept obtained in part B. (D) Create a scatterplot for the data above and plot the regression line. (E) What are the predicted heights for wives whose husbands’ heights are: 70, 69, and 67?

Expert Solution

orchestra answered 2 years ago

2. The mean height of American women in their twenties is about 64.3 inches, and the...

2. The mean height of American women in their twenties is about 64.3 inches, and the standard deviation is about 2.7 inches. The mean height of men the same age is about 69.9 inches, with standard deviation about 3.1 inches. Suppose that the correlation between the heights of husbands and wives is about r = 0.5. What are the slope and intercept of the regression line of the husband’s height on the wife’s height in young couples? Interpret the slope...

height is approximately nornamlly distributed. for women, the mean height is 64 inches and with a...

height is approximately nornamlly distributed. for women, the mean height is 64 inches and with a standard deveatikn of 2.56inches. a. what proportion of women are taller than 72 inches? b.how tall are women in the 90th percentile? c. how tall are women in the 40th percentile?

In a sample of 10 randomly selected women, it was found that their mean height was...

In a sample of 10 randomly selected women, it was found that their mean height was 63.4 inches. From previous studies, it is assumed that the standard deviation σ is 2.4 and that the population of height measurements is normally distributed. Construct the 99% confidence interval for the population mean. (60.8, 65.4) (58.1, 67.3) (61.4, 65.4) (59.7, 66.5)

Suppose that the mean height for women at a large company is assumed to be 70...

Suppose that the mean height for women at a large company is assumed to be 70 inches with a standard deviation of 3 inches. If the women are placed randomly into classes of 36 each, what will be the standard deviation of the class means for height (i.e. the standard error of the mean)? Using your answer to part (a), what is the z score for a class whose average height is 67.2 inches? What is the two-tailed p-value for...

QUESTION 9 Use the following table to answer the next two questions. In Terms of USD...

QUESTION 9 Use the following table to answer the next two questions. In Terms of USD Country Bid Ask Canada $.9225 $.9265 Euro $1.45 $1.48 What is the ask quote for Canadian dollars in terms of euros? .639 .6233 .6362 1.34 QUESTION 10 What is the ask quote for euros in terms of Canadian dollars? 1.5326 1.565 1.6043 .6233 QUESTION 11 A dealer quotes the euro at $1.1345-55 and the peso at $.1056-61. How many euros would you receive in...

A half-century ago, the mean height of women in a particular country in their 20s was...

A half-century ago, the mean height of women in a particular country in their 20s was 64.7 inches. Assume that the heights of today's women in their 20s are approximately normally distributed with a standard deviation of 1.72 inches. If the mean height today is the same as that of a half-century ago, what percentage of all samples of 22 of today's women in their 20s have mean heights of at least 65.74 inches?

The height of women (ages 20 to 29) are approximaltely normally distributed with a mean of...

The height of women (ages 20 to 29) are approximaltely normally distributed with a mean of 68 inches and standard deviation of 3.8 inches. The heights of men (ages 20 to 29) are approximately normally distributed with a mean height of 71.5 inches and a standard deviation of 3.4 inches. A) Use the z- score to compare a woman that is 5 feet 7 inches and a man that is 5 feet 7 inches tall. B) If a z-score of...

The following data was collected on the height (inches) and weight (pounds) of women swimmers. Height...

The following data was collected on the height (inches) and weight (pounds) of women swimmers. Height Weight 68 132 64 108 62 102 65 115 66 128 Provide a regression analysis from the height and weight data. SUMMARY OUTPUT Regression Statistics Multiple R 0.9603 R Square 0.9223 Adjusted R Square 0.8963 Standard Error 4.1231 Observations 5 ANOVA df SS MS F Significance F Regression 1 605 605 35.5882 0.0094 Residual 3 51 17 Total 4 656 Coefficients Standard Error t...

Perform a hypothesis test for population mean: Nearly 30 years ago the mean height for women...

Perform a hypothesis test for population mean: Nearly 30 years ago the mean height for women 20 years old and older was 63.7 inches. A recent random sample of 45 women who are 20 years old and older had a mean of 63..9 inches. Perform a hypothesis test on the following hypotheses: Null Hypothesis - the population mean is equal to 63.7 inches and the Alternate Hypothesis - the population mean is greater than 63.7 inches. Use a level of...

The height, X , of American teens is distributed normally with a mean u = 65.5...

The height, X , of American teens is distributed normally with a mean u = 65.5 inches and the standard deviation o = 2.5 inches. Find the probability of each of the following events. a. ? < 67 inches b. 64 < X < 67 inches

Question