In: Chemistry
Calculate the pressure in cm H2O exerted in the closed end of an apparatus if the atmospheric pressure is 720.0 torr and the height of the water coloumn is 22.3cm.
atmospheric pressure = 720.0 torr
height of the water coloumn = 22.3cm.= 0.223 m
1 torr = 133.3 pa
atmospheric pressure = 720.0 torr = 95976 Pa
pressure exerted = atmospheric pressure + pressure head
= Po + gh
= 95976 + (1000 x 9.8 x 0.223)
= 98161.4 Pa
1 Pa = 0.0101972 cm H2O
98161.4 Pa = 98161.4 x 0.0101972
= 1000.97 cm H2O
pressure exerted = 1000.97 cm H2O