Given the following information: energy of sublimation of Li( s)= 166 kilojoules per mole find bond...

Given the following information:
energy of sublimation of Li( s)= 166 kilojoules per mole
find bond energy of HCL= 427 kilojoules per mole
ionization energy of Li(g) =520 kilojoules per mole
electron affinity of Cl(g) =-349 kilojoules per mole
lattice energy of LiCl(s)=-829 kilojoules per mole
bond energy of H2= 432 kilojoules per mole

calculate the net change in energy for the following reaction:

2Li(s)+2HCl(g)------->2LiCl(s) + H2(g)

Expert Solution

2Li(s)+2HCl(g) ------->2LiCl(s) + H2(g)

Li(s)     →    Li(g)                           heat of sublimation of Li(s) = 166kJ/mol------->1
HCl(g)     →     H(g) + Cl(g)          bond energy of HCl = 427 kJ/mol------------->2
Li(g)     →    Li+ (g)   +   e-            ionizationenergy of Li(g) = 520 kJ/mol-------->3
Cl(g) +    e- →     Cl-(g)               electron afinity of Cl(g) = -349kJ/mol--------->4
Li+ (g)   + Cl-(g)    →   LiCl(s)       lattice energy of LiCl(s) = -829kJ/mol--------->5
H2 (g)   →   2H(g)                           bondenergy of H2     = 432kJ/mol------------>6

dH = 2xeq1 + 2xeq2 - eq6 +2xeq4 + 2xeq5 + 2xeq3

=> dH = (2x166) + (2x427) - 432 + (2x-349) + (2x-829) + (2x520)

=> dH = - 562 kJ

queen_honey_blossom answered 3 years ago

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