In: Chemistry
Given the following information:
energy of sublimation of Li( s)= 166 kilojoules per mole
find bond energy of HCL= 427 kilojoules per mole
ionization energy of Li(g) =520 kilojoules per mole
electron affinity of Cl(g) =-349 kilojoules per mole
lattice energy of LiCl(s)=-829 kilojoules per mole
bond energy of H2= 432 kilojoules per mole
calculate the net change in energy for the following reaction:
2Li(s)+2HCl(g)------->2LiCl(s) + H2(g)
2Li(s)+2HCl(g) ------->2LiCl(s) + H2(g)
Li(s) →
Li(g)
heat of sublimation of Li(s) = 166kJ/mol------->1
HCl(g) → H(g) +
Cl(g) bond
energy of HCl = 427 kJ/mol------------->2
Li(g) → Li+
(g) +
e-
ionizationenergy of Li(g) = 520 kJ/mol-------->3
Cl(g) + e- →
Cl-(g)
electron afinity of Cl(g) = -349kJ/mol--------->4
Li+ (g) + Cl-(g) →
LiCl(s) lattice energy of
LiCl(s) = -829kJ/mol--------->5
H2 (g) →
2H(g)
bondenergy of H2 =
432kJ/mol------------>6
dH = 2xeq1 + 2xeq2 - eq6 +2xeq4 + 2xeq5 + 2xeq3
=> dH = (2x166) + (2x427) - 432 + (2x-349) + (2x-829) + (2x520)
=> dH = - 562 kJ