In: Statistics and Probability
Consider the following observations on a receptor binding measure (adjusted distribution volume) for a sample of 13 healthy individuals: 22, 39, 40, 42, 43, 46, 52, 58, 63, 66, 68, 70, 73.
(a)
Is it plausible that the population distribution from which this sample was selected is normal?
( yes or no) , it ( is or is not)
plausible that the population distribution is normal.
(b)
Calculate an interval for which you can be 95% confident that at least 95% of all healthy individuals in the population have adjusted distribution volumes lying between the limits of the interval. (Round your answers to three decimal places.)
( , ) |
(c)
Predict the adjusted distribution volume of a single healthy individual by calculating a 95% prediction interval. (Round your answers to three decimal places.)
( , ) |
How does this interval's width compare to the width of the interval calculated in part (b)?
This interval's width is ( less or greater)
than the width of the interval calculated in part (b).
a) yes, it is
b)
sample mean x= | 52.462 |
sample size n= | 13.000 |
sample std deviation s= | 15.2786 |
std error sx=s/√n= | 4.2375 |
for 95% CI; and 12 df, critical t= | 2.1790 | |
margin of error E=t*std error = | 9.234 | |
lower bound=sample mean-E = | 43.228 | |
Upper bound=sample mean+E= | 61.695 | |
from above 95% confidence interval for population mean =(43.228 ,61.695) |
c)
std errror of mean ='s=s*√(1+1/n)= | 15.855 | |
for 95% CI; and 12 df, value of t= | 2.1790 | |
margin of error E=t*std error = | 34.5488 | |
lower bound=sample mean-margin of error = | 17.913 | |
Upper bound=sample mean +margin of error= | 87.010 |
95% prediction interval for population mean =(17.913 ,87.010)
This interval's width is greater than the width of the interval calculated in part (b)