In: Accounting
Data for Oriole Corporation’s maintenance costs is shown below.
Units Produced |
Total Cost |
|||||||
July | 18,500 | $39,263 | ||||||
August | 32,896 | 49,344 | ||||||
September | 37,008 | 56,540 | ||||||
October | 22,616 | 40,156 | ||||||
November | 41,120 | 76,586 | ||||||
December | 39,064 | 63,736 |
Compute the variable- and fixed-cost elements using the regression
analysis. Present your solution in the form of a cost equation. (We
recommend that you use the Intercept and Slope functions in Excel.)
(Round intercept to 2 decimal places e.g. 1.25 and
slope to 5 decimal places e.g. 1.25125.)
Intercept | $ | |
Slope | $ |
The cost equation is: $ + $ per unit produced = Total cost |
Months | Units Produced(X) | Cost(Y)(in $) | Square of X | X*Y(in $) |
July | 18,500 | 39,263 | 34,22,50,000 | 72,63,65,500 |
August | 32,896 | 49,344 | 1,08,21,46,816 | 1,62,32,20,224 |
September | 37,008 | 56,540 | 1,36,95,92,064 | 2,09,24,32,320 |
October | 22,616 | 40,156 | 51,14,83,456 | 90,81,68,096 |
November | 41,120 | 76,586 | 1,69,08,54,400 | 3,14,92,16,320 |
December | 39,064 | 63,736 | 1,52,59,96,096 | 2,48,97,83,104 |
Total | 1,91,204 | 3,25,625 | 6,52,23,22,832 | 10,98,91,85,564 |
Unit Variable Cost (b) = nΣxy − (Σx)(Σy) /nΣx^2 − (Σx)^2 |
Total Fixed Cost (a) = Σy − bΣx / n |
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So here n =6 ,Σx =191,204 Σy =325,625, Σx^2=6,522,322,832 ,Σxy =10,989,185,564 | ||||
Variable cost per unit(b) =6*10,989,185,564 - (191,204*325,625) / 6*6,522,322,832 - 191,204^2 | ||||
Variable cost per unit(b) =(65,935,113,384 - 62,360,802,500) / (39,133,936,992 - 36,558,969,616) | ||||
Variable cost per unit(b) = $3,674,310,884 / $2,574,967,376 =$1.42693 per unit | ||||
Total Fixed cost =325,625 - ($1.42693*191,204) / 6 | ||||
Total Fixed cost =($325,625 - $272,835) / 6 | ||||
Total Fixed cost =$52,790 / 6 =$8,798.38 | ||||
The cost volume formula is: | ||||
Y =$8,798.38 + $1.42693X | ||||
Slope | 8798.38 | |||
Intercept | 1.42693 | |||