In: Statistics and Probability
14. An alcohol awareness task force at a Big-Ten university sampled 200 students after the midterm to ask them whether they went bar hopping the weekend before the midterm or spent the weekend studying, and whether they did well or poorly on the midterm. The following result was obtained. (Please show the calculation process)
Did Well on Midterm |
Did Poorly on Midterm |
|
Studying for Exam |
80 |
20 |
Went Bar Hopping |
30 |
70 |
Referring to above table, what is the probability that a randomly selected student did well on the midterm and went bar hopping the weekend before the midterm?
15. What is the probability that a randomly selected student did well on the midterm or went bar hopping the weekend before the midterm?
16. Referring to above table, the events "Did Well on Midterm" and "Studying for Exam" are
Did Well on Midterm | Did Poorly on Midterm | Total | |
Studying for Exam | 80 | 20 | 100 |
Went Bar Hopping | 30 | 70 | 100 |
Total | 110 | 90 | 200 |
14. Probability that a randomly selected student did well on the midterm and went bar hopping the weekend before the midterm?
Answer : The number of students who did well and went bar hopping is 30.
p = 30/200
15. What is the probability that a randomly selected student did well on the midterm or went bar hopping the weekend before the midterm?
Answer : The number of students who did well or went bar hopping is 80+30+70 = 180.
p = 180/200
16. Referring to above table, the events "Did Well on Midterm" and "Studying for Exam" are
Events A and B are independent if the equation P(A∩B) = P(A) P(B) holds true.
P("Did Well on Midterm" and "Studying for Exam") =P("Did Well on Midterm") * P( "Studying for Exam")
80/200 =110/200 * 100/200
0.4 not equal to 0.275
Events "Did Well on Midterm" and "Studying for Exam" are statistically dependent.
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