Question

write an awk script that works as wc command.

Answer 1

`Hey,

Note: Brother if you have any queries related the answer please do comment. I would be very happy to resolve all your queries.

If you can use grep, simulating the line count is easy: just count how many times something that matches always happens:

grep -c '^' filename

This should output the same as wc -l (but it might report one more line if the file doesn't end in a newline).

To get the number of words, you can use the following pipeline:

grep -o '[^[:space:]]\+' filename | grep -c '^'

You need grep that supports the -o option which prints each matching string to a line of its own. The expression matches all non-space sequences, and piping them into what we used in the previous case just counts them.

To get the number of characters (wc -c), you can use

LC_ALL=C grep -o . filename | grep -c '^'

Setting LC_ALL is needed if your locale supports UTF-8, otherwise you'd count wc -m. You need to add the number of newlines to the output number, so

echo $(( $( grep -c '^' filename ) 
         + $( LC_ALL=C grep -o . filename | grep -c '^' ) ))

Kindly revert for any queries

Thanks.