In: Operations Management
Problem 10-21
Design specifications require that a key dimension on a product measure 102 ± 15 units. A process being considered for producing this product has a standard deviation of eight units.
a. What can you say (quantitatively) regarding the process capability? Assume that the process is centered with respect to specifications. (Round your answer to 4 decimal places.)
Process capability index
b. Suppose the process average shifts to 94. Calculate the new process capability. (Round your answer to 4 decimal places.)
New process capability index
c. What is the probability of defective output after the process shift? (Use Excel's NORM.S.DIST() function to find the correct probability. Round "z" values to 2 decimal places. Round probabilities to 4 decimal places (0.####).)
Probability of defective output
Given |
Average of data |
µ |
15.93 |
Standard deviation of Data |
σ |
4.98 |
|
Specification |
102 +/- 15 |
||
Upper Specification Limit (USL) |
USL = Target + tolerance |
USL = 102 + 15 USL = 117 |
|
Lower Specification Limit (LSL) |
LSL = Target - tolerance |
USL = 102 - 15 USL = 87 |
|
Part a. |
Average of data |
µ, consider the process is centered |
µ = 102 |
Standard deviation of Data |
σ = 8 units |
σ = 8 |
|
Upper Cpk |
Upper Cpk = [(USL - µ) / (3σ)] Upper Cpk = (117 – 102)/(3*8) |
0.625 |
|
Lower Cpk |
Lower Cpk = [(µ - LSL) / (3σ)] Lower Cpk = (102 – 87)/(3*8) |
0.625 |
|
Process Cpk |
Cpk = Min (Upper Cpk, Lower Cpk) = Min ([(USL - µ) / (3σ)],[(µ - LSL) / (3σ)]) |
=min(0.625, 0.625) = 0.625 |
|
ANS a. |
Process capability Index = 0.625 |
||
Part b. |
Average of data |
µ |
µ = 94 |
Standard deviation of Data |
σ = 8 units |
σ = 8 |
|
Upper Cpk |
Upper Cpk = [(USL - µ) / (3σ)] Upper Cpk = (117 – 94)/(3*8) |
0.2917 |
|
Lower Cpk |
Lower Cpk = [(µ - LSL) / (3σ)] Lower Cpk = (94 – 87)/(3*8) |
0.9583 |
|
Process Cpk |
Cpk = Min (Upper Cpk, Lower Cpk) = Min ([(USL - µ) / (3σ)],[(µ - LSL) / (3σ)]) |
=min(0.2917, 0.9583) = 0.2917 |
|
ANS b. |
Process capability Index = 0.2917 |
||
Part c. |
Average of data |
µ |
µ = 94 |
Standard deviation of Data |
σ = 8 units |
σ = 8 |
|
Fraction of output less than 87 and more than 117 are defective items |
Probability of defective = P(87 < x > 117) = P (x <= 87) + P(X >= 117) |
||
Fraction of output <= 87 minutes |
P(X <87) = P(z <= z87) z-score for X = 87 z87= (X – µ)/σ z87= (87 – 94)/8 = -0.875 From excel, P(z <-0.875) = (=NORMDIST(-0.875)) = 0.1908 |
P(X <87) = 0.1908 |
|
Fraction of output >= 117 minutes |
P(X > 117) = 1 - P(X <= 117) P(z <= z117) z-score for X = 117 z117= (X – µ)/σ z117= (117 – 94)/8 = 2.875 From excel, P(z <2.875) = (=NORMDIST(-2.875)) = 0.9979 |
P(X > 117) = 1 - P(X <= 117) P(X > 117) = 1 – 0.9979 P(X > 117) = 0.00202 |
|
Percentage of defective output = P(87 < x > 117) |
P(87 < x > 117) = P(x <= 87) + P(x >= 117) = 0.1908 + 0.00202 =0.1928 |
P(87 < x > 117) = 0.1928 |
|
ANS C |
Percentage of defective output = 0.1928 |