In: Math
Question 1 contains the actual values for 12 periods (listed in order, 1-12). In Excel, create forecasts for periods 6-13 using each of the following methods: 5 period simple moving average; 4 period weighted moving average (0.63, 0.26, 0.08, 0.03); exponential smoothing (alpha = 0.23 and the forecast for period 5 = 53); linear regression with the equation based on all 12 periods; and quadratic regression with the equation based on all 12 periods. Round all numerical answers to two decimal places.
1. The actual values for 12 periods (shown in order) are:
(1)
45 (2)
52
(3)
48
(4)
59 (5)
55 (6)
54 (7)
64 (8)
59 (9)
72 (10)
66 (11)
67 (12)
78
Using a 5 period simple moving average, the forecast for period 13
will be:
2. Using
the 4 period weighted moving average, the forecast for period 13
will be:
3. With
exponential smoothing, the forecast for period 13 will be
4.
With linear regression, the forecast for period 13 will be:
5. With
quadratic regression, the forecast for period 13 will be:
6. Considering
only the forecasts for period 6-12, what is the lowest MAD value
for any of the methods?
1. 5 period simple moving average is calculated as
For example the forecast for period 6 is obtained by deviding the sum of values from periods 1 to 5 by 5
The calculations are below
The values are
The forecast for period 13 will be 68.4
2. 4 period weighted moving average with the weights (0.63, 0.26, 0.08, 0.03) is calculated as
Use the following
get the following
Using the 4 period weighted moving average, the forecast for period 13 will be: 74
3. exponential smoothing (alpha = 0.23 and the forecast for period 5 = 53)
The forecast for period t+1 is
The forecast for period 6 is (having given that the forecast for period 5 is 53 and the value of period 5 is 55)
The calculation for the rest is
The values are
With exponential smoothing, the forecast for period 13 will be 66.29
4. linear regression with the equation based on all 12 periods
The linear model that we want ot estimate is
where Y is the value for period t
is the intercept of the regression line
is the slope coefficient for t
is a random disturbance
We use data-->data analysis--regression to setup
get the following
the estimated regression equation is
The forecast for period 6 is
The calculations are below
get the values
With linear regression, the forecast for period 13 will be: 76.08
5. quadratic regression
the model that we want to estimate is
where Y is the value for period t
is the intercept of the regression line
is the slope coefficient for t
is the slope coefficient for
is a random disturbance
We add a new column for t-square and using data-->data analsysis-->regression setup the regression
get the following
The estimated regression line is
the forecast for period 6 is
The formula for the rest is
The values are
With quadratic regression, the forecast for period 13 will be: 77.52
Mean Absolute Deviation (MAD) is calculated as below
MAD for each of the 5 forecast is below
the values are
The lowest MAD for any methods is 4.07 for quadratic regression