Question

In: Statistics and Probability

It is believed that the women with some education beyond high school (H) are more likely...

It is believed that the women with some education beyond high school (H) are more likely to use contraceptives compared to women with an education level at or below a high school level (L). A study was conducted to test this claim and found out that 201 among 613 low-educated women (L) use contraceptives and 228 out of 848 women with some education beyond high school (H) use contraceptives. Does it appear that better-educated women are more likely to use contraceptives compared to low-educated women? Conduct a test of hypothesis at 5% level of significance. What are the null and alternative hypotheses for the test?

Solutions

Expert Solution

Here we have :

201 among 613 low-educated women (L) use contraceptives.

so nL = 613, xL = 201

Hence proportion of low educated women use contraceptives is :

  

= 0.33

Also we have , 228 out of 848 women with some education beyond high school (H) use contraceptives.

so nH = 848, xH = 228

Hence proportion of women with education beyond high school use contraceptives is :

  

= 0.27

Claim : Better-educated women are more likely to use contraceptives compared to low-educated women.

Hence the hypothesis are :

H0 : PL = PH v/s H1 : PL < PH

The test statistic is given by,

Where,

= 0.29

Hence the test statistic value is given by,

= -2.49

p value = p ( z < -2.49 )
= 0.0064 ------------( using excel formula "=norm.s.dist(-2.49,1)" )

Here p value < ( 0.05)

Hence we reject null hypothesis.

Conclusion :

There are sufficient evidence to support the claim that better-educated women are more likely to use contraceptives compared to low-educated women.


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