Question

In: Physics

A stuntman drives a car at a speed of 20m/s off a 28 m high cliff....

A stuntman drives a car at a speed of 20m/s off a 28 m high cliff. The road leading to the cliff is inclined upward at an angle of 20 degree.

A) How far from the bees of the cliff does the car land?

B) What is the car's impact speed?

write everything specifically please

Expert Solution

A) Let the car land a distance of d from the bees of the cliff.

The initial speed of the car is u=20 m/s.

The incline angle is 20^o.

The height of the cliff h=-28 m.

Let the horizontal component of the car's speed is v_x.

The verticle component of the car's speed is v_y.

The verticle acceleration is -g.

Now we know

Note: The negative value of t is ignored because of time always positive.

The horizontal distance covered by the car is

b) Let the impact speed of the car is v_i.

The initial speed of the vertical component is v_y.

The final speed of the verticle component is

The impact speed of the car is

The impact speed of the car is 30.815958 m/s or 30.82 m/s approximately.

genius_generous answered 2 years ago

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