A flat sheet of chrystalline quartz has a thickness of 2.48 cm. It is on top...

A flat sheet of chrystalline quartz has a thickness of 2.48 cm. It is on top of a flat sheet of fused quartz that has a thickness of 1.50 cm. Light strikes the chrystalline quartz perpendicularly and travels through it and then through the fused quartz. In the time it takes the light to travel through the two sheets, how far (in cm) would it have traveled in a vacuum?

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A flat sheet of crystalline quartz has athickness of 3.5 cm. It is on top of aflat sheet of diamond that has a thicknessof 2.0 cm. Light strikes the crystalline quartz perpendicularly and travels throughit and then through the diamond. In thetime it takes the light to travel through the two sheets, how farwould it have traveled in a vacuum?

x₁ = 3.5 cm = 0.035 m
x₂ = 2 cm = 0.02 m

What you need:
The indices of refraction, n, for quartz and diamond (I'll usen₁ and n₂, respectively). You'll needto look these up in your textbook.
Equation for index of refraction, n = c/v, or v = c/n
Equation of motion, x = v t, or t = x/v

t_total = t₁ + t₂ =

The distance traveled by light in a vacuum,
x = c t = = n₁x₁ +n₂x₂

genius_generous answered 1 month ago

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