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A flat sheet of chrystalline quartz has a thickness of 2.48 cm. It is on top...

A flat sheet of chrystalline quartz has a thickness of 2.48 cm. It is on top of a flat sheet of fused quartz that has a thickness of 1.50 cm. Light strikes the chrystalline quartz perpendicularly and travels through it and then through the fused quartz. In the time it takes the light to travel through the two sheets, how far (in cm) would it have traveled in a vacuum?

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I have solved this question earlier with different figures. Please workout using yours figures. If you need any further help just PM me. If I have helped you please rate me 5 stars first (before you rate anyone else).

A flat sheet of crystalline quartz has athickness of 3.5 cm. It is on top of aflat sheet of diamond that has a thicknessof 2.0 cm. Light strikes the crystalline quartz perpendicularly and travels throughit and then through the diamond. In thetime it takes the light to travel through the two sheets, how farwould it have traveled in a vacuum?


x1 = 3.5 cm = 0.035 m
x2 = 2 cm = 0.02 m

What you need:
The indices of refraction, n, for quartz and diamond (I'll usen1 and n2, respectively). You'll needto look these up in your textbook.
Equation for index of refraction, n = c/v, or v = c/n
Equation of motion, x = v t, or t = x/v

ttotal = t1 + t2 =

The distance traveled by light in a vacuum,
x = c t = = n1x1 +n2x2

genius_generous answered 2 months ago
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