In: Statistics and Probability
For a healthy human, a body temperature follows a normal distribution with Mean of 98.2 degrees Fahrenheit and Standard Deviation of 0.26 degrees Fahrenheit. For an individual suffering with common cold, the average body temperature is 100.6 degrees Fahrenheit with Standard deviation of 0.54 degrees Fahrenheit. Simulate 10000 healthy and 10000 unhealthy individuals and answer questions 14 to 16.
14. If person A is healthy and person B has a cold, which of the events are the most likely? Pick the closest answer.
15. What would be a range [A to B], which would contain 68% of healthy individuals? Pick the closest answer.
16. What is the approximate probability that a randomly picked, unhealthy individual (one with the cold) would have body temperature above 101 degrees Fahrenheit? Pick the closest answer.
A random experiment was conducted where a Person A tossed five coins and recorded the number of “heads”. Person B rolled two dice and recorded the sum the two numbers. Simulate this scenario (use 10000 long columns) and answer questions 10 to 13.
10. Which of the two persons (A or B) is more likely to get the number 4?
11. Which of the two persons will have higher Median among their outcomes?
12. What is the probability that person B obtains number 5 or 6?
13. Which of the persons has higher probability of getting the number 3 or smaller?
14 - > (a) person B have higher temperature than 101 degrees,
because (b) cannot be true as if person a has higher temperature than 99 than he has cold most likely as mentioned by sd and mean of healthy people
(c) AND (d) also cannot be true as they also dont satisfy the given sd and mean
15 - > (a) because of the AtoB not BtoA ....... as the healthy person's sd is .26 than the 68% data will lie in 97.94-98.46, if it was BtoA than the (c) option will be true
16 - > (a) as most of the unhealthy above 2nd sd will come somewhat near 90%
10 - > (b) because only person b is rolling the dice
11 - > (b) again person b has higher median as he is rolling dice and recording the sum compared to person A who has recorded the heads in five the coins the median in case of coins can be atmost 3 but the sum of dice can be in between 2-12 which has a higher chance of getting higher median than coins
12 - > (b) as for getting 5 or 6 there are only (2,4), (4,2), (1,5), (5, 1), (3,2), (2, 3), (3,3), (1, 4), (4,1)
so the probability is 9/36= 25%
13 - > (a) person A has more chances as they can range in between [0,5] but in case person B the smallest value will start from 2 = 1+1
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