The molar solubility of cobalt(II) sulfide in a 0.247 M ammonium sulfide solution is

Expert Solution

Ksp of CoS = 4.0×10^–21

concentration of S-2 = 0.247 M

CoS ---------------> Co+2 + S^-2

S 0.247

Ksp = [Co+2][S^-2]

4.0×10^–21 = S x 0.247

S = 1.62 x 10^-20 M

molar solubility of cobalt(II) sulfide = 1.62 x 10^-20 M

queen_honey_blossom answered 1 year ago

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