In: Physics

# Did the values of μ measured directly and indirectly agree? As the tension is increased, does...

1. Did the values of μ measured directly and indirectly agree?

2. As the tension is increased, does the number of segments increase or decrease when the frequency is kept constant?

3. As the frequency is increased, does the number of segments increase or decrease when the tension is kept constant?

4. As the tension is increased, does the speed of the wave increase, decrease, or stay the same when the frequency is kept constant?

5. As the frequency is increased, does the speed of the wave increase, decrease, or stay the same when the tension is kept constant?

6. Suppose that String #1 is twice as dense as String #2, but both have the same tension and the same length. If each of the strings is vibrating in the fundamental mode, which string will have the higher frequency?

## Solutions

##### Expert Solution

As the tension is increased, does the number of segments increase or decrease when the frequency is kept constant?

number of segments decreases because more the tension, lesser are the segments

______________

As the frequency is increased, does the number of segments increase or decrease when the tension is kept constant?

The number of segments increases as the frequency increases because frequency and the number of segments are directly related.

____________

As the tension is increased, does the speed of the wave increase, decrease, or stay the same when the frequency is kept constant

v = sqrt ( T/u)

so, The speed will increase

_______________

As the frequency is increased, does the speed of the wave increase, decrease, or stay the same when the tension is kept constant

The speed stays the same as long as tension is kept constant.

__________________

Suppose that String #1 is twice as dense as String #2, but both have the same tension and the same length. If each of the strings is vibrating in the fundamental mode, which string will have the higher frequency

more the thickness , lesser the frequency

so,

String #2 will have the higher frequency.

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