A stream of water vapor flowing at a rate of 452 mol/h is brought from 700.0...

A stream of water vapor flowing at a rate of 452 mol/h is brought from 700.0 °C and 10 bar to 400.0 °C and 1 atm. Using Steam Tables, Estimate the required cooling rate (in kW). Use five significant figures in your calculations.

Solutions

Expert Solution

Given: Flowrate of water vapor, =452 mol/h

Initial temperature and pressure respectively, T₁=700⁰C and P₁=10 bar

Final temperature and pressure respectively, T₂=400⁰C and P₂=1 atm

The required cooling rate, is

where is the Molar flow rate

is the Change in specific enthalpy of water vapor (steam)

Obtain specific enthalpy from Properties of Superheated Steam table.

At T₁=700⁰C and P₁=10 bar, specific enthalpy

At T₂=400⁰C and P₂=1 atm=1.01325 bar,

Thus cooling rate is

where 18.02*10^-3 kg/mol is the Molar mass of water

Therefore, the required cooling rate is = -1.45931 kW

Amanda K answered 1 year ago

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