A professor has kept track of test scores for students who have attended every class and...

A professor has kept track of test scores for students who have attended every class and for students who have missed one or more classes. below are scores collected so far.

perfect: 80,86,85,84,81,92,77,87,82,90,79,82,72,88,82

missed 1+:61,80,65,64,74,78,62,73,58,72,67,71,70,71,66

1. Evaluate the assumptions of normality and homoscedasticity

2. conduct a statistical test to assess if exam scores are different between perfect attenders and those who have missed class

3. What is the meaning of the 95% confidence interval given from the R code. What does the 95% CI explain compared to the hypothesis test and how does the 95% CI relate to the test statistic and p value

Expert Solution

milcah answered 4 months ago

Suppose a professor gives an exam to a class of 40 students and the scores are...

Suppose a professor gives an exam to a class of 40 students and the scores are as follows. (Type the data set in StatCrunch.) 35 44 46 47 47 48 49 51 53 54 55 55 57 57 57 58 59 59 59 59 60 60 60 60 60 62 62 62 64 68 69 70 72 73 73 75 75 77 82 88 Top 10% of scores receive an A Bottom 10% of scores receive an F Scores between...

A statistics professor gave a 5-point quiz to the 50 students in his class. Scores on...

A statistics professor gave a 5-point quiz to the 50 students in his class. Scores on the quiz could range from 0 to 5: The following frequency table resulted: (1.5 points) Quiz Score f rf cf crf c% 5 4 .08 50 1.00 100% 4 10 .20 46 .96 96% 3 14 .28 36 .72 72% 2 10 .20 22 .44 44% 1 8 .16 12 .24 24% 0 4 .08 4 .08 8% 1. Compute the values that define...

Students who took STAT 1001 can be divided into two groups; those who attended class regularly...

Students who took STAT 1001 can be divided into two groups; those who attended class regularly and benefited from the awesome lecture and those who did not attend and missed out on great information. Two independent random samples of 20 students were taken from each group (i.e. n1 = n2 = 20), and their final exam scores were registered. The average grades for those who attended regularly and those who did not were 71.5% and 61.5%, respectively. Let’s assume that...

Here are some test scores from eight students in a class such as yours: Second Test...

Here are some test scores from eight students in a class such as yours: Second Test Score: 158, 162, 144, 162, 136, 158, 175, 153 First Test Score: 145, 140, 145, 170, 145, 175, 170, 160 A.) Pick an explanatory variable, and explain your choice B.) Using this data make a scatter plot C.) Find the correlation, and graph the line of best fit on the scatter plot

Test scores for a sample of 20 students in a managerial accounting class are shown. (a)...

Test scores for a sample of 20 students in a managerial accounting class are shown. (a) At α = .05, is there a difference in the population median scores on the two tests? Fill in the right side of the worksheet below. (Round your Rank, R+, and R– answers to 1 decimal place. Negative values should be indicated by a minus sign.) Student Test 1 Test 2 d |d| Rank R+ R– 9 52 53 12 95 96 8 71...

A class consisting of 10 students takes a test. The scores are approximately normally distributed with...

A class consisting of 10 students takes a test. The scores are approximately normally distributed with a mean of 74 and a standard deviation of 11. The teacher wants to curve the grades in the following manner: the top 5% get As, the next highest 12% get Bs, the bottom 5% get Fs, and the next lowest 12% get Ds. The rest will get Cs. Find the Z-scores for each line and the test score corresponding to each z score

A professor hypothesizes that students who earn a C or better in her class spend more...

A professor hypothesizes that students who earn a C or better in her class spend more time outside of class studying than students who receive a D or F. She collects the following data from two samples of students. What does she conclude? Number of hours studying per week for C or better students: 8, 4, 4, 2, 1, 5, 3, 2, 3 Number of hours studying per week for D or F students: 6, 2, 1, 0, 3, 2,...

A certain test preparation course is designed to improve students' SAT Math scores. The students who...

A certain test preparation course is designed to improve students' SAT Math scores. The students who took the prep course have a mean SAT Math score of 526, while the students who did not take the prep course have a mean SAT Math score of 515. Assume that the population standard deviation of the SAT Math scores for students who took the prep course is 44.6 and for students who did not take the prep course is 45.2. The SAT...

An MPH professor claims that 50 % of the students in his class has a median...

An MPH professor claims that 50 % of the students in his class has a median weight different from 140 lb. He collects the weight of a random sample of 22 students. Enter the following data in SPSS and perform a binomial test using the standard method. Alpha level = 0.05 (Make sure to save your data before start analyzing the data). 135 119 106 135 180 108 128 160 143 175 170 205 195 185 182 150 175 190...

a professor has learned that six students in her class of 19 will cheat on the...

a professor has learned that six students in her class of 19 will cheat on the exam. She decides to focus her attention on eight randomly chosen students during the exam. A. what is the probability that she finds at least one the students cheating? B. what is the probability that she finds at least one of the students cheating if she focuses on nine randomly chosen students?

Question